我试图通过传递最小和最大日期来获取启用CDC的表上的净更改。但抛出低于错误。更改数据捕获错误
Msg 313, Level 16, State 3, Line 24
An insufficient number of arguments were supplied for the procedure or function cdc.fn_cdc_get_net_changes_ ... .
我的代码如下:
DECLARE @CDate DATE = '2013-03-18' --This is the date after the CDC was enabled on the table
DECLARE @count INT;
DECLARE @lsnStartDatetime DATETIME;
DECLARE @lsnEndDateTime DATETIME;
DECLARE @begin_time DATETIME ,
@end_time DATETIME ,
@from_lsn BINARY(10) ,
@to_lsn BINARY(10);
SELECT @lsnStartDatetime = CAST(CAST(@CDate AS NVARCHAR(10)) + ' 00:00:00' AS DATETIME)
SELECT @lsnEndDateTime = CAST(CAST(@CDate AS NVARCHAR(10)) + ' 23:59:59' AS DATETIME)
SET @from_lsn = sys.fn_cdc_map_time_to_lsn('smallest greater than or equal',
@lsnStartDatetime);
SET @to_lsn = sys.fn_cdc_map_time_to_lsn('largest less than or equal',
@lsnEndDateTime);
if exists (select * from sys.objects where name = 'EmployeeCDCbyDate' and type = 'u')
drop table etl.EmployeeCDCbyDate
SELECT *
FROM cdc.fn_cdc_get_net_changes_employee(@from_lsn, @to_lsn, N'all')
难道是from_lsn和to_lsn从sys.fn_cdc_map_time_to_lsn犯规配以映射aginst CDC表 '员工'
下面的代码作品获得精细;但它会从min max lsn's中获得所有净变化。
DECLARE @min_lsn BINARY(10) = sys.fn_cdc_get_min_lsn ('employee')
DECLARE @max_lsn BINARY(10) = sys.fn_cdc_get_max_lsn()
SELECT * FROM cdc.fn_cdc_get_net_changes_employee(@min_lsn, @max_lsn, 'all') ORDER BY 1 desc
我需要的是获得给定日期的cdc实例的最小和最大lsn并获得该日期的净变化。任何线索?
编辑:
当我在一堆表使这正常工作与第一个表。
例:
USE ERP
EXEC sys.sp_cdc_disable_db
EXEC sys.sp_cdc_enable_db
EXEC sys.sp_cdc_enable_table @source_schema = N'dbo',
@source_name = N'Employee',
@capture_instance = 'Employee',
@supports_net_changes =1,
@role_name = NULL
EXEC sys.sp_cdc_enable_table @source_schema = N'dbo',
@source_name = N'StoreListing',
@capture_instance = 'StoreListing',
@supports_net_changes =1,
@role_name = NULL
Go
这正常工作与Employee表。如果我更改CDC启用的顺序(如果我先将商店列表和员工下一个),那么它可以在员工列表中正常工作。
这些都在MSDN论坛和连接是我的帖子虽然:-) 。我期待是否有人想出了替代方法来做到这一点。 – Sreedhar 2013-05-28 07:37:21
对不起。我应该比较代码。 Edit中的代码适用于第一个表格 - 是否适用于其他表格? – Stoleg 2013-05-28 08:01:23