我采用序列JSON.Net多维列表,我有使其正确序列化的问题。发行序列化JSON多维名单
下面是结果我从这个预期:
"children": [ {
"children": [ {
"children": [ {
"date_added": "12995911618983970",
"id": "8",
"name": "NestedNestedURL",
"type": "url",
"url": "http://url.com/"
} ],
"date_added": "12995911579845538",
"date_modified": "12995911618983970",
"id": "5",
"name": "NestedNestedFolder",
"type": "folder"
}, {
"date_added": "12995911609609970",
"id": "7",
"name": "NestedURL",
"type": "url",
"url": "http://url.com/"
} ],
"date_added": "12995911570603538",
"date_modified": "12995911609609970",
"id": "4",
"name": "NestedFolder",
"type": "folder"
}, {
"children": [ {
"date_added": "12995911631570970",
"id": "9",
"name": "NestedURL2",
"type": "url",
"url": "http://url.com/"
} ],
"date_added": "12995911589790970",
"date_modified": "12995911631570970",
"id": "6",
"name": "NestedFolder2",
"type": "folder"
}
然而,这比结果我真正得到很大的不同。这里的问题,我认为,这是多重的URL可以属于一个单一的文件夹,多个文件夹到一个文件夹,但我不确定如何实现这一点。这是我目前使用的代码:
public void Sync()
{
Browser browser = new Chrome();
SortableBindingList<Bookmark> marks = browser.ReturnBookmarks();
SortableBindingList<object> newmarks = new SortableBindingList<object>();
int count = 0;
newmarks.Add(new json_top());
json_top top = newmarks[0] as json_top;
top.roots = new json_root();
List<object> roots = new List<object>();
Folder bookmarks_bar = new Folder();
Folder other = new Folder();
List<Object> barlist = new List<Object>();
List<object> otherlist = new List<object>();
List<object> children = new List<object>();
List<string> existingFolders = new List<string>();
bookmarks_bar.date_added = ToChromeTime(marks[0].added);
bookmarks_bar.name = "Bookmarks bar";
other.date_added = ToChromeTime(marks[0].added);
other.name = "Other bookmarks";
bool isBookmarkBar = true;
Folder folder = new Folder();
foreach (Bookmark mark in ordered)
{
List<string> fullpathlist = mark.fullPath.Split('\\').ToList();
int count1 = 0;
if (currentPath != mark.fullPath)
{
folder = (createFolder(fullpathlist, fullpathlist[0], mark));
folder.children.Add(setChild(fullpathlist, folder, mark, 1));
count++;
}
json_URL u = new json_URL();
u.date_added = ToChromeTime(mark.added);
u.id = id;
u.name = mark.title;
u.url = mark.url;
folder.children.Add(u);
if(isBookmarkBar)
barlist.Add(folder);
else
{
otherlist.Add(folder);
}
}
bookmarks_bar.children = barlist;
other.children = otherlist;
top.roots.bookmark_bar = (bookmarks_bar);
top.roots.other = other;
string json = JsonConvert.SerializeObject(newmarks, Formatting.Indented);
File.WriteAllText(@"c:\person.json", json);
}
Folder setChild(List<string> fullPathList, Folder parent, Bookmark mark, int count)
{
if (count < fullPathList.Count)
{
Folder child = new Folder();
child.date_added = ToChromeTime(mark.added);
child.id = id;
child.name = fullPathList[count];
Folder LIST = setChild(fullPathList, child, mark, count + 1);
child.children= LIST;
return child;
}
}
public class Folder
{
public List<folderAndURL> children { get; set; }
public long date_added { get; set; }
public long date_modified
{
get { return 0; }
}
public int id { get; set; }
public string name { get; set; }
public string type
{
get { return "folder"; }
}
}
这里是我的输出从该代码得到:
"children": [
{
"children": {
"date_added": 12995893609609970,
"id": 0,
"name": "NestedURL",
"type": "url",
"url": "http://url.com/"
},
"date_added": 12995893609609970,
"date_modified": 0,
"id": 0,
"name": "NestedFolder",
"type": "folder"
},
{
"children": {
"date_added": 12995893618983970,
"id": 1,
"name": "NestedNestedURL",
"type": "url",
"url": "http://url.com/"
},
"date_added": 12995893618983970,
"date_modified": 0,
"id": 1,
"name": "NestedFolder",
"type": "folder"
},
{
"children": {
"date_added": 12995893631570970,
"id": 2,
"name": "NestedURL2",
"type": "url",
"url": "http://url.com/"
},
"date_added": 12995893631570970,
"date_modified": 0,
"id": 2,
"name": "NestedFolder2",
"type": "folder"
}
那么,怎样才能更改我的代码相匹配的输入和输出?就像我说的,它似乎是关于多个文件夹没有被应用到一个父文件夹的东西。
编辑:我已经上传完整版本的代码here的,因为我切出由于空间的某些部分。
什么是你先从结构?再看看你在这里粘贴的代码。它不完整,不会编译。 –
@JeffMercado我上剪下来的空间用途的代码,但我可以把它放在一个引擎收录或张贴整个事情,如果你喜欢? –
再看一遍。你有两个'Sync()'方法具有相同的确切签名。其中第一个甚至不是完整的。它看起来像是在'for'循环中间被切断了。不可能知道它应该做什么。 –