查找数组中最小值的索引号

Question

我必须返回12个数字数组中最小值的索引号。我每次运行它时都会得到12个结果。这里是我的代码：

minRain = leastRain(months); 

public static int leastRain (double[] mon4){ 
    int lowest = (int) mon4[0]; 

    for (int index=1; index<mon4.length; index++){ 
     if (mon4[index]<lowest) 
      lowest = index; 
    } 
    return lowest; 
} 

System.out.println("The month with the lowest amount of rain is: " + (minRain + 1)); 

Answer 1

您需要存储lowest_seen和lowest_index。现在你正在比较价值< last_index

Answer 2

这是一个愚蠢的错误，你做了 - 你指定的变量，而不是一个数组值。这样做：

public static int leastRain (double[] mon4){ 
    int lowest = 0; 

    for (int index=1; index<mon4.length; index++){ 
     if (mon4[index]<mon4[lowest]) 
      lowest = index; 
    } 
    return lowest; 
} 

Answer 3

这条语句的含义是什么？

int lowest = (int) mon4[0]; 

您将数组的第一个值保存为最低值，然后再与数组值进行比较。您实际上是将索引与数组值进行比较。

if (mon4[index]<lowest) // comparing lowest as an array value 
    lowest = index;  // saving the index as the lowest value 

你应该这样做。

if (mon4[index]<mon4[lowest]) // comparing value of 'index' 'vs. 'lowest' index location 
    lowest = index; 

Answer 4

要指定数组值的lowest，所以改变它，如下图所示：

public static int leastRain (double[] mon4){ 
    int lowestIndex = 0;//set index as 0 instead of array value 
    int lowestValue = mon4[0]; 
    for (int index=1; index<mon4.length; index++){ 
     if (mon4[index] < lowestValue) 
      lowestIndex = index; 
    } 
    return lowestIndex; 
}