“Missing”）error

Question

我正在研究询问用户名称和年龄的代码。

var name; 
var age; 

name = prompt("What is your name?"); 
age = prompt("What is your age?"); 

的代码设置重复他们的名字和年龄回给他们，然后if语句使用一个要么给他们发送消息说“你还年轻”如果年龄变量是50

下

虽然我有问题。我无法打印字符串，告诉用户他们输入的年龄和姓名是什么。我收到一个语法错误，告诉我有一个意外的字符串。

问题的代码是这样的：

console.log("You're name is " +name " and you are " +age "years old."); 

的代码工作正常，如果我只打印一个变量到控制台，像这样：

console.log("You're name is " +name.); 

希望你们能帮助我。

全码：

var name; 
var age; 

name = prompt("What is your name?"); 
age = prompt("What is your age?"); 

console.log("You're name is " +name " and you are " +age "years old.") 

var printNameAndAge = function() { 
    if (age>50) { 
     console.log("Dang you're old."); 
    } 
    else { 
     console.log("You're pretty young, "+name); 
     alert("You're pretty young, "+name); 
    } 
}; 

printNameAndAge(); 

Answer 1

console.log("Your name is " + name + " and you are " + age + " years old."); 

要插入变量内联，你既需要后和之前，使用连接运算符。

Answer 2

您在name之后缺少两个+，而在age之后缺少一个。请修正如下：

console.log("You're name is " +name + " and you are " +age+ "years old."); 

Answer 3

你忘了一些加号！

console.log("You're name is " +name " and you are " +age "years old."); 

应该

console.log("You're name is " +name +" and you are " +age+ "years old.");