你好我想根据business1的下拉列表显示business2的数据的数据,但business1的变化()我得到了数据作为响应,但如何使用id在第二个下拉列表中打印它。我没有得到成功的反应。如何使用Id打印下拉列表的选项。 我在mozila的firefox控制台中得到了回复,但是我不知道如何成功返回它,然后如何在第二个下拉列表中打印。没有成功响应ajax函数
<!-- ajax code starts here -->
<script>
$(document).on('change', 'select.Business1', function(){
var business1 = $('select.Business1 option:selected').val();
alert(business1);
var value = $(this).val();
$.ajax({
type:"POST",
data: { business1:business1 },
url: '<?php echo site_url('client_area/select_business_sub_cat'); ?>',
sucess : function (data){
alert(1);
var abc = $('#business2').html(data);
}
});
});
</script>
<!-- ajax code ends here -->
型号功能
public function select_business_sub_cat()
{
$business1 = $this->input->post('business1');
$result_sub_cat1 = $this->db->query("select category.id,subcategory.* From category LEFT JOIN subcategory ON category.id = subcategory.category_id where category.id = '$business1'");
$row_cat1 = $result_sub_cat1->result();
$data = array(
'id' => $row_cat1['0']->id,
'name' => $row_cat1['0']->name
);
echo "<option value='" . $row_cat1['0']->id . "'>" . $row_cat1['0']->name . "</option>";
// return $this->output->set_output($data);
}
视图 -
<div class="form-group">
<label>Business 1</label>
<select name="txtBusiness1" id="" style="height: 30px;width: 100%;" class="Business1">
<option value=""> Select Business </option>
<?php
$result_cat1 = $this->db->query("select * from category");
$row_cat1 = $result_cat1->result();
?>
<?php foreach($row_cat1 as $item){ ?>
<option value="<?php echo $item->id; ?>"><?php echo $item->name; ?></option>
<?php } ?>
</select>
</div>
<div class="form-group">
<label>Business 2</label>
<select name="txtBusiness2" id="business2" style="height: 30px;width: 100%;" class="Business2">
<option value=""> Select Business2 </option>
</select>
ohk谢谢你兄弟...我现在得到了警惕(1),现在我得到了mozila的回复,比如现在我想在id business2的下拉列表中回显它。但错误是ReferenceError:数据未定义。 – Bhavin
尝试提醒数据而不是1 ...接下来会发生什么? –
兄弟我在警报中空白。 – Bhavin