Ajax和Django render_to_response（如何呈现成功函数内的响应）

Question

目前我正在尝试实现登录验证系统。我正在使用ajax，以便用户可以在不被重定向到其他页面的情况下获得响应。我的ajax函数发送用户输入的电子邮件和密码，并在回调函数中获取消息，可以有三种类型：电子邮件，密码或实际的HttpResponse对象。但我不知道如何使用ajax和jQuery来渲染给定的http响应对象。 location.href是一个选项吗？我正在粘贴下面的代码。

在javascript中：

function loginSubmit(email, password) { 
    var d= "email=" + email + "&password=" + password; 
    $.ajax({ 
     url: "/login", 
     type: "POST", 
     dataType: "text", 
     data: d, 
     success: function(m) { 
      if (m == "email") { 
       $("#emailMessage").html("There is no account associated with this email address."); 
       $("#emailError").show(); 
       $("#emailError").fadeOut(5000, function() {}); 
      } else if (m == "password") { 
       $("#emailMessage").html("There is no account associated with this email address."); 
       $("#emailError").show(); 
       $("#emailError").fadeOut(5000, function() {}); 
      } else { 

      } 
     } 
    }); 
} 

鉴于功能：

def login(request): 
    json = request.POST 
    e = json['email'] 
    p = json['password'] 

    u = User.objects.filter(email=e) 

    if (len(u)): 
     up = User.objects.filter(email=e, password=p) 
     if (len(up)): 
      return render_to_response('profile.html', context_instance=RequestContext(request)) 
     else: 

      data = "password" 
      c = RequestContext(request, {'result':data}) 
      t = Template("{{result}}") 
      datatype=u"application/javascript" 
      return HttpResponse(t.render(c), datatype) 
    else: 
     data = "email" 
     c = RequestContext(request, {'result':data}) 
     t = Template("{{result}}") 
     datatype=u"application/javascript" 
     return HttpResponse(t.render(c), datatype) 

P.S.目前，我正在使用虚拟模板和HttpResponse将数据发送到ajax成功回调函数。有没有更有效的方法来完成这个（发回json数据）？我会等待你的回复家伙！

Answer 1

from django.contrib.auth import authenticate, login as auth_login 

def login(request): 

    # Use authentication framework to check user's credentials 
    # http://djangosnippets.org/snippets/1001/ for auth backend 
    user = authenticate(
       email = request.POST['email'], 
       password = request.POST['password'],) 

    if user is not None: 
     # Use Auth framework to login user 
     auth_login(request, user) 
     return render_to_response('profile.html', 
       context_instance=RequestContext(request)) 

    else: 
     # Return Access Denied 
     # Never return bad email/bad password. This is information leakage 
     # and helps hackers determine who uses your platform and their emails. 
     return HttpResponse("Failed: Bad username or password", status=403) 


function loginSubmit(email, password) { 
    $.ajax({ 
     url: "/login", 
     type: "POST", 
     data: {email:email, password:password}, 
     success: function(data) { 
      var returned_html = $(data); 
      $("#target_profile_area").clear().append(returned_html); 
     }, 
     error: function(jqXHR) { 
      if (jqXHR.statusCode == 403) { 
       $("#loginMessage").text("Your login details are incorrect"); 
      } else { 
       $("#loginMessage").text("Error Contacting Server"); 
      } 
      $("#loginError").show(); 
      $("#loginError").fadeOut(5000, function() {}); 
     } 
    }); 
}