我有下面的代码:无错DB2更新不执行
BEGIN
DECLARE cmd VARCHAR(1024); DECLARE attr CHAR(10);
DECLARE attr2 CHAR(10);
DECLARE at_end INTEGER DEFAULT 0;
DECLARE not_found CONDITION FOR SQLSTATE '02000';
DECLARE updstr1 VARCHAR(1024);
DECLARE updstr2 VARCHAR(1024);
DECLARE c1 CURSOR FOR SELECT cmd, attr, attr2
FROM commandtbl2;
DECLARE CONTINUE HANDLER FOR not_found SET at_end = 1;
SET updstr1 = 'update commandtbl3 t2 set t2.XXXX = attr where t2.cmd=cmd';
SET updstr2 = 'update commandtbl3 t2 set t2.XXXX= attr2 where t2.cmd=cmd';
OPEN c1;
ins_loop: LOOP
FETCH c1 INTO cmd, attr, attr2;
IF at_end = 1 THEN
LEAVE ins_loop;
ELSEIF cmd != '' THEN
ITERATE ins_loop;
END IF;
set updstr1= REPLACE(updstr1,'XXXX','attr');
set updstr2= REPLACE(updstr2,'XXXX','attr2');
EXECUTE IMMEDIATE updstr1;
EXECUTE IMMEDIATE updstr2;
END LOOP;
CLOSE c1;
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这一切都运行,但是当我检查commandtbl3什么也没有更新。所有的值都是NULL,但应该被替换。这两个表中有7行,5个具有匹配的cmd值,所以这5行应该更新。
我不确定替换是不是工作或执行即时。
随着调试我发现,updstr1和2变量在替换后是空的......但为什么?
你能帮我吗? 谢谢, TheVagabond
如这里请求是commandtbl3和2的定义:
CREATE TABLE "TEST"."COMMANDTBL3" (
"ID" INTEGER NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1 INCREMENT BY 1 MINVALUE 1 MAXVALUE 2147483647 NO CYCLE CACHE 2 NO ORDER),
"CMD" VARCHAR(1024 OCTETS) NOT NULL,
"ATTR" CHAR(10 OCTETS),
"ATTR2" CHAR(10 OCTETS),
CONSTRAINT "CC1455789123996" PRIMARY KEY
("ID")
)
CREATE TABLE "TEST"."COMMANDTBL2" (
"ID" INTEGER NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1 INCREMENT BY 1 MINVALUE 1 MAXVALUE 2147483647 NO CYCLE CACHE 2 NO ORDER),
"CMD" VARCHAR(1024 OCTETS) NOT NULL,
"ATTR" CHAR(10 OCTETS),
"ATTR2" CHAR(10 OCTETS),
CONSTRAINT "CC1455789123996" PRIMARY KEY
("ID")
)
COmmandtbl3具有CMD等于除2行commandtbl2(7行总数)和attR和attR2是NMULL在commandtbl3 。我要被写入通过更新commandtbl3与替换的命令,这样我就可以有占位符commandtbl2 ATTR和attR2值XXXX
这里是工作代码:
如果有人在这里有相同的概率是工作代码,即使从开始的(while循环现在等)改变:
BEGIN
DECLARE EOF INTEGER DEFAULT 0;
DECLARE cmd VARCHAR(1024); DECLARE attr CHAR(10);
DECLARE attr2 CHAR(10);
DECLARE not_found CONDITION FOR SQLSTATE '02000';
DECLARE updstr1 VARCHAR(1024);
DECLARE updstr2 VARCHAR(1024);
DECLARE stmt1 STATEMENT;
DECLARE stmt2 STATEMENT;
DECLARE c1 CURSOR FOR SELECT cmd, attr, attr2
FROM commandtbl2 order by cmd;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET EOF = 1;
SET updstr1 = 'update commandtbl3 t2 set t2.XXXX = ? where t2.cmd= ?';
SET updstr2 = 'update commandtbl3 t2 set t2.XXXX= ? where t2.cmd= ?';
set updstr1= REPLACE(updstr1,'XXXX','attr');
set updstr2= REPLACE(updstr2,'XXXX','attr2');
insert into temptbl(text1,text2) values(updstr1,updstr2);
prepare stmt1 from updstr1;
prepare stmt2 from updstr2;
OPEN c1;
WHILE EOF = 0 DO
FETCH from c1 INTO cmd, attr, attr2;
EXECUTE stmt1 using attr, cmd;
EXECUTE stmt2 using attr2, cmd;
END WHILE;
CLOSE c1;
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检查如何在动态的语句中使用的参数再次手动。提示:将会有一个'PREPARE'语句,'EXECUTE'将有'USING'子句。 – mustaccio
我知道,从其他编码语言嵌入SQL语句准备,我需要的是只使用SQL的时候也是一样,我没有一个参数标记我刚刚替换字符串。 – Thevagabond
您确实希望在后面的''cmd'其中t2.cmd = cmd'由您提取到前面,一个变量来代替神奇,不是吗?不会发生。 – mustaccio