多行命令批处理注释

Question

我想知道是否可以在批处理文件命令中有注释。具体地讲，我有一个长SED如下命令：

@SED -r -e "s/.../.../"^ 
    -e "s/.../.../"^ 
    -e "s/.../.../"^ 
    fileName >outFileName 

我想将注释添加到每个“-e”选项，如图所示在下面的实施例：

:: Option #1: At the end of the line 
@SED -r -e "s/.../.../"^ // First comment 
    -e "s/.../.../"^  // Second comment 
    -e "s/.../.../"^  // Third comment 
    fileName >outFileName 

:: Option #2: Between lines 
@SED -r 
    @REM First comment 
    -e "s/.../.../"^ 
    @REM Second comment 
    -e "s/.../.../"^ 
    @REM Third comment 
    -e "s/.../.../"^ 
    fileName >outFileName 

有什么办法可以做到这一点？

Answer 1

试试这个。我没有sed，所以我只是用echo进行测试。

@echo off 
:: Option #1: At the end of the line 
echo SED -r -e "s/.../.../" %= First comment =%^ 
    -e "s/.../.../" %= second comment =%^ 
    -e "s/.../.../" %= third comment =% 

:: Option #2: Between lines 
echo SED -r^ 
    %= First comment =%^ 
    -e "s/.../.../"^ 
    %= second comment =%^ 
    -e "s/.../.../"^ 
    %= third comment =%^ 
    -e "s/.../.../" 

pause 

输出

SED -r -e "s/.../.../"  -e "s/.../.../"  -e "s/.../.../" 
SED -r  -e "s/.../.../"  -e "s/.../.../"  -e "s/.../.../" 
Press any key to continue . . .