根据输入将文本输入转换为int或double

Question

我有一个JFrame，我从文本字段获取输入并将其转换为整数。 我也想将它转换为double，如果它是一个double，并且可能会返回一条消息，如果它不是int或double。我怎样才能做到这一点？

我当前的代码：

int textToInt = Integer.parseInt(textField[0].getText()); 

Answer 1

String text = textField[0].getText(); 
try { 
    int textToInt = Integer.parseInt(text); 
    ... 
} catch (NumberFormatException e) { 
    try { 
     double textToDouble = Double.parseDouble(text); 
     ... 
    } catch (NumberFormatException e2) { 
     // message? 
    } 
} 

为了保持精度，立即解析为BigDecimal。 这parseDouble当然不是语言环境特定的。看到

Answer 2

try { 
    int textToInt = Integer.parseInt(textField[0].getText()); 
} catch(NumberFormatException e) { 
    try { 
     double textToDouble = Double.parseDouble(textField[0].getText()); 
    } catch(NumberFormatException e2) { 
     System.out.println("This isn't an int or a double"; 
    } 
} 

Answer 3

boolean isInt = false; 
boolean isDouble = false; 
int textToInt = -1; 
double textToDouble = 0.0; 

try { 
    textToInt = Integer.parseInt(textField[0].getText()); 
    isInt = true; 
} catch(NumberFormatException e){ 
    // nothing to do here 
} 

if(!isInt){ 
    try { 
     textToDouble = Double.parseDouble(textField[0].getText()); 
     isDouble = true; 
    } catch(NumberFormatException e){ 
     // nothing to do here 
    } 
} 

if(isInt){ 
// use the textToInt 
} 

if(isDouble){ 
// use the textToDouble 
} 
if(!isInt && !isDouble){ 
// you throw an error maybe ? 
} 

Answer 4

检查如果字符串包含小数点。

if(textField[0].getText().contains(".")) 
    // convert to double 
else 
    // convert to integer 

没有必要抛出异常。

在执行上述操作之前，您可以检查字符串是否是使用正则表达式的数字。一种方式是模式[0-9]+(\.[0-9]){0,1}。我不是最好的正则表达式，所以请纠正我，如果这是错误的。

Answer 5

你可以尝试一系列嵌套的try-渔获物：

String input = textField[0].getText(); 
try { 
    int textToInt = Integer.parseInt(input); 
    // if execution reaches this line, it's an int 
} catch (NumberFormatException ignore) { 
    try { 
     double textToDouble = Double.parseDouble(input); 
     // if execution reaches this line, it's a double 
    } catch (NumberFormatException e) { 
     // if execution reaches this line, it's neither int nor double 
    } 
}