如何获取在gridview中点击的android切换按钮的位置?如何获取在gridview中单击的togglebutton的位置?
如果我使用下面的示例代码,我没有得到位置的Toast消息。
public class HelloGridView extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
GridView gridview = (GridView) findViewById(R.id.gridview);
gridview.setAdapter(new ToggleButtonAdapter(this));
gridview.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View v, int position,
long id) {
Toast.makeText(HelloGridView.this, "" + position, Toast.LENGTH_SHORT).show();
}
});
}
}
与肘适配器:
public class ToggleButtonAdapter extends BaseAdapter {
private Context mContext;
public ToggleButtonAdapter(Context c) {
mContext = c;
}
@Override
public int getCount() {
return 5;
}
@Override
public Object getItem(int position) {
return null;
}
@Override
public long getItemId(int position) {
return 0;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View view;
LayoutInflater inflater = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
if (convertView == null) { // reuse it if it already exists
view = (View) inflater.inflate(R.layout.items, null);
} else {
view = (View) convertView;
}
ToggleButton toggleButton = (ToggleButton) view.findViewById(R.id.toggleButton1);
TextView textView = (TextView) view.findViewById(R.id.textView1);
textView.setText("Toggle Button " + position);
/*toggleButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
ToggleButton t = (ToggleButton) v.findViewById(R.id.toggleButton1);
Toast.makeText(mContext, Boolean.toString(t.isChecked()), Toast.LENGTH_SHORT).show();
}
});*/
return view;
}
}
取消对拨动听者的那部分玩,告诉我怎么去的位置。是否有一种方法可以在构建网格视图时将一些数据注入切换按钮,以便以后参考?我无法找到阅读ToggleButton javadoc的方法。
非常感谢!
编辑:
糟糕!这里的布局:
main.xml中
<GridView
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/gridview"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:columnWidth="90dp"
android:numColumns="auto_fit"
android:verticalSpacing="10dp"
android:horizontalSpacing="10dp"
android:stretchMode="columnWidth"
android:gravity="center"
>
</GridView>
items.xml: AdapterView.ContextMenuInfo信息=(适配器视图:
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="horizontal">
<LinearLayout
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical">
<TextView
android:text="Some label"
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_margin="10dp"/>
<ToggleButton
android:id="@+id/toggleButton1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_margin="10dp"/>
</LinearLayout>
</LinearLayout>
位置作为参数传递给getView功能已经过去了。 'info.position`不会返回相同的东西吗? – basilisk 2011-02-18 03:31:20
如果你是对的,杰森问如何获得onClick方法的位置。 info.position只是getView方法中的参数位置 – 2011-02-18 03:36:17