我正在阅读有关C编程的投票,并在poll(2)手册页中构建了一个应用程序。
这里是例子:
轮询C Linux函数如何工作?
#include<stdio.h>
#include <stropts.h>
#include <poll.h>
#include <fcntl.h>
int main() {
struct pollfd fds[2];
int timeout_msecs = -1;
int ret;
int i;
/* Open STREAMS device. */
fds[0].fd = open("/home/jeshwanth/mywork/poll/dev0", O_RDONLY);
fds[1].fd = open("/home/jeshwanth/mywork/poll/dev1", O_RDONLY);
fds[0].events = POLLOUT | POLLWRBAND;
fds[1].events = POLLOUT | POLLWRBAND;
while (1) {
ret = poll(fds, 2, timeout_msecs);
if (ret > 0) {
/* An event on one of the fds has occurred. */
for (i = 0; i < 2; i++) {
if (fds[i].revents != 0) {
/* Priority data may be written on device number i. */
printf(
"Priority Data may be written on device number %d POLLWRBAND\n",
i);
}
if (fds[i].revents = !0) {
/* Data may be written on device number i. */
printf("Data may be written on device number %d POLLOUT\n",
i);
}
if (fds[i].revents = !0) {
/* A hangup has occurred on device number i. */
printf("A hangup has occurred on device number %d\n", i);
}
}
}
}
return 0;
}
注:装置0和DEV1是正常的文件。当我运行程序时,如果在dev0和dev1中没有发生事件,则显示消息。但是我期待有人写入文件时,只有它应该显示消息。我错了吗?
没有那些'printf'应为每个封闭那些来执行'if'分支具备的条件'0'。 – oldrinb
@oldrinb谢谢,我在发布之前测试它,所以我误以为=,现在它是!=。忘了那些printf的,怎么ret> 0?如果文件没有变化? –
你的代码仍然是错误的,但现在它会打印后面的2条消息,因为它们的封闭'if'分支都具有'!0'的条件。 – oldrinb