无法从Laravel命令启动线程

Question

我是新来的pthreads在PHP中。我已经了解到，不可能从apache通过web服务器启动它，所以我已经使用laravel命令从命令行运行它，但是当我调用 start（） 线程方法

时，出现此错误

PHP Fatal error: Uncaught Exception: Serialization of 'Closure' is not allowed in [no active file]:0 

Stack trace: 

#0 {main} 

thrown in [no active file] on line 0 

但是，只要我调用run方法，错误就会消失，这是不行的。

我真的很感谢任何帮助，我可以得到。

我的命令的处理方法进行这样

public function handle() 
{ 
    $threads = ["Thread One", "Thread Two"]; 
    $threadList=[]; 
    foreach ($threads as &$thread){ 
     //$id++; 
     $this->info($thread); 
     $testThread = new TestThread($thread); 
     $testThread->start(); 
     $threadList[] = $testThread; 
    } 

    foreach ($threadList as $thread){ 
     $this->info("waiting for thread ". $thread->getThreadID()); 
     $thread->join(); 
     $this->info($thread->getThreadID()."done "); 
     //echo $thread->getThreadID().'<br/>'; 
    } 
} 

和我ThreadClass是这个

namespace App\Engine\Threads\ThreadClass; 


use Illuminate\Support\Facades\Log; 

class TestThread extends \Thread 
{ 
    private $threadID; 

    public function __construct($threadID) 
    { 
     $this->threadID = $threadID; 
    } 

    /** 
    * @return mixed 
    */ 
    public function getThreadID() 
    { 
     return $this->threadID; 
    } 

    public function run() 
    { 
     $this->threadID = $this->threadID.''.mt_rand(4000, 5000); 

    } 


} 

Answer 1

我找到了解决我的问题，通过添加以下参数启动功能

$testThread->start(PTHREADS_INHERIT_ALL^PTHREADS_INHERIT_CLASSES); 

此问题提供Fatal error while starting threads within symfony command