XSLT子节点从父节点复制

Question

我想从父节点复制节点到子节点。我不确定如何实现这一目标。

我的源XML

<Root1> 
    <Family1> 
     <Childrens> 
     <Child> 
      <ChildFirstName>Robin1</ChildFirstName> 
      <ChildLastName>Jackman1</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 

       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin2</ChildFirstName> 
      <ChildLastName>Jackman2</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 

       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin3</ChildFirstName> 
      <ChildLastName>Jackman3</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 

       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     </Childrens> 
    </Family1> 
    </Root1> 

我想获得输出作为

<Root1> 
    <Family1> 
     <Childrens> 
     <Child> 
      <ChildFirstName>Robin1</ChildFirstName> 
      <ChildLastName>Jackman1</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 
        <ChildFirstName>Robin1</ChildFirstName> 
        <ChildLastName>Jackman1</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address> 
       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin2</ChildFirstName> 
      <ChildLastName>Jackman2</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 
        <ChildFirstName>Robin2</ChildFirstName> 
        <ChildLastName>Jackman2</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address> 
       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin3</ChildFirstName> 
      <ChildLastName>Jackman3</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 
        <ChildFirstName>Robin3</ChildFirstName> 
        <ChildLastName>Jackman3</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address> 
       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     </Childrens> 
    </Family1> 
    </Root1> 

我想在XSLT 1.0解决方案。

我想这些节点复制到子节点

    <ChildFirstName>Robin3</ChildFirstName> 
        <ChildLastName>Jackman3</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address> 

感谢。

Answer 1

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> 

<xsl:template match="@* | node()"> 
    <xsl:copy> 
    <xsl:apply-templates select="@* | node()"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="ParticipentNames"> 
    <xsl:copy> 
    <xsl:apply-templates select="ancestor::Child/ChildFirstName | ancestor::Child/ChildLastName | ancestor::Child/Address"/> 
    </xsl:copy> 
</xsl:template> 

</xsl:stylesheet> 

应该足够了（可能要添加<xsl:output indent="yes"/>和<xsl:strip-space elements="*"/>更好的格式）。