将父节点的一部分复制到子节点XSLT

我想从父节点复制节点到子节点。我不确定如何实现这一目标。将父节点的一部分复制到子节点XSLT

我的源XML

<Root1> 
    <Family1> 
     <Childrens> 
     <Child> 
      <ChildFirstName>Robin1</ChildFirstName> 
      <ChildLastName>Jackman1</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 

       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin2</ChildFirstName> 
      <ChildLastName>Jackman2</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 

       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin3</ChildFirstName> 
      <ChildLastName>Jackman3</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 

       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     </Childrens> 
    </Family1> 
    </Root1>

我想获得输出作为

<Root1> 
    <Family1> 
     <Childrens> 
     <Child> 
      <ChildFirstName>Robin1</ChildFirstName> 
      <ChildLastName>Jackman1</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 
        <ChildFirstName>Robin1</ChildFirstName> 
        <ChildLastName>Jackman1</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address> 
       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin2</ChildFirstName> 
      <ChildLastName>Jackman2</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 
        <ChildFirstName>Robin2</ChildFirstName> 
        <ChildLastName>Jackman2</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address> 
       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     <Child> 
      <ChildFirstName>Robin3</ChildFirstName> 
      <ChildLastName>Jackman3</ChildLastName> 
      <Address> 
      <Street1>Street1</Street1> 
      <State>State</State> 
      <Country>Country</Country> 
      </Address> 
      <Activities> 
      <Sports> 
       <Cricket> 
       <ParticipentNames> 
        <ChildFirstName>Robin3</ChildFirstName> 
        <ChildLastName>Jackman3</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address> 
       </ParticipentNames> 
       </Cricket> 
      </Sports> 
      </Activities> 
     </Child> 
     </Childrens> 
    </Family1> 
    </Root1>

我想在XSLT 1.0解决方案。

我想这些节点复制到子节点

    <ChildFirstName>Robin3</ChildFirstName> 
        <ChildLastName>Jackman3</ChildLastName> 
        <Address> 
        <Street1>Street1</Street1> 
        <State>State</State> 
        <Country>Country</Country> 
        </Address>

感谢。

来源

2012-05-07 KRP

反向XPath不推荐!!!! –

您的源XML和期望的输出非常大，您尚未准确解释源XML文档中的哪些节点应该完全复制到哪个元素下。此外，您的XSLT代码引用了当前提供的源XML文档中不存在的元素。由于这些事实，目前这个问题很混乱，很容易猜测。请编辑问题并精确指定所有必要的信息。 –

<?xml version="1.0" encoding="utf-8"?> 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
    <xsl:output method="xml" indent="yes"/> 

    <xsl:template match="@* | node()"> 
     <xsl:copy> 
      <xsl:apply-templates select="@* | node()"/> 
     </xsl:copy> 
    </xsl:template> 
    <xsl:template match="/OrderItem/ProductionInformation/GSItem"> 
    <xsl:copy> 
     <xsl:apply-templates select="@*|node()"/> 
     <xsl:for-each select="/OrderItem"> 
     <xsl:apply-templates select="@*|node()[name()!='ProductionInformation']"/> 
     </xsl:for-each> 
    </xsl:copy> 
    </xsl:template> 

</xsl:stylesheet>

来源

2012-05-07 08:29:06

将父节点的一部分复制到子节点XSLT

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