如何将PartialFunction与另一个函数结合并返回PartialFunction？

Question

我有以下类：

class MessageProcessorActor(private val destination : ActorRef) extends Actor{ 
    override def receive: Receive = { 
    case _ => 
    destination ! { 
     case MyActor.TracableMessage(msg) => MyActor.TracableMessage("Processed + " + msg) 
     case MyActor.Message(msg) => MyActor.Message("Processed + " + msg) 
     case _ => "Processed + " + _ 
    }(_) 
    } 
} 

object MyActor{ 
    case class TracableMessage(private val msg: String) extends Message(msg) 
    case class Message(private val msg: String) 
} 

凡为

type Receive = PartialFunction[Any, Unit] 

在这里，我试图避免宣布val拿着PartialFunction[Any, Any]并调用它这样Recieve定义。但编译器拒绝此代码。它打印：

Error:(12, 6) ';' expected but '(' found. 
    }(_) 
    ^

是否有一个简短的方法来做这样的事情？

Answer 1

你为什么试图这样写？跟着怎么了

class MessageProcessorActor(private val destination : ActorRef) extends Actor{ 
    override def receive: Receive = { 
    case MyActor.TracableMessage(msg) => { 
     destination ! MyActor.TracableMessage("Processed + " + msg) 
    } 
    case MyActor.Message(msg) => { 
     destination ! MyActor.Message("Processed + " + msg) 
    } 
    case _ => { 
     destination ! "Processed + " + _ 
    } 
    } 
} 

object MyActor{ 
    case class TracableMessage(private val msg: String) extends Message(msg) 
    case class Message(private val msg: String) 
}