计算子查询select语句中的聚合值SQL

列'Order.OrderId'在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

这里是我的查询：

SELECT vc.VehicleCategoryName, 
    (SELECT COUNT(oc.OrderId) FROM [Order] oc WHERE oc.OrderId = o.OrderId AND c.OrderStatusId = 2) AS completedTrip, 
    (SELECT COUNT(oc.OrderId) FROM [Order] oc WHERE oc.OrderId = o.OrderId AND oc.OrderStatusId = 3) AS CanceledTrip 
FROM [Order] o 
INNER JOIN VehicleCategory vc ON vc.VehicleCategoryId = o.VehicleCategoryId 
WHERE CAST(o.OrderTime AS date) = '2017-03-13' 
GROUP BY vc.VehicleCategoryName;

我想我的形成数据是这样的：

VehicleCategoryName|Completed Trips | Canceled Trips 
    Bugdet    100    20 
    Premier    50    10 
    Rocket    20    20

请帮忙什么是错的，我用骨料在做什么？

来源

2017-03-15 naveed ahmed

请不要使用JavaScript/HTML片段格式，除非它是Javascript或HTML或CSS – GrabNewTech

哪个DBMS您使用的？在你的问题中有非标准的SQL –

您不需要关联的子查询。您可以使用COUNT代替CASE。

试试这个：

select vc.VehicleCategoryName, 
    count(case when o.OrderStatusId = 2 then 1 end) as completedTrip, 
    count(case when o.OrderStatusId = 3 then 1 end) as CanceledTrip 
from [Order] o 
inner join VehicleCategory vc on vc.VehicleCategoryId = o.VehicleCategoryId 
where cast(o.OrderTime as date) = '2017-03-13' 
group by vc.VehicleCategoryName

它使用的事实，上述情况语句只会在匹配条件和空返回1，否则和count函数计算唯一的非空值。

来源

2017-03-15 06:03:23 GurV

谢谢，但是如果我必须从另一个表像Like Fare table中获取值来计算收益，该怎么办？对每个类别的总收入？ –

@naveedahmed - 你可以加入这个表。 – GurV

可否请您编辑您的答案请我的表是票价有外键OrderId –

SELECT 
vc.VehicleCategoryName , 
SUM(CASE WHEN o.OrderStatusId = 2 THEN 1 ELSE 0 END) as completedTrip , 
SUM(CASE WHEN o.OrderStatusId = 3 THEN 1 ELSE 0 END) as CanceledTrip 

FROM [Order] o 

inner join VehicleCategory vc 
on vc.VehicleCategoryId = o.VehicleCategoryId 
where cast(o.OrderTime as date) = '2017-03-13' 

group by vc.VehicleCategoryName

来源

2017-03-15 06:03:23 Luv

请试试这个，

SELECT vc.VehicleCategoryName, 
    (SELECT COUNT(oc.OrderId) FROM [Order] oc WHERE oc.OrderId = o.OrderId AND c.OrderStatusId = 2) AS completedTrip, 
    (SELECT COUNT(oc.OrderId) FROM [Order] oc WHERE oc.OrderId = o.OrderId AND oc.OrderStatusId = 3) AS CanceledTrip 
FROM [Order] o 
INNER JOIN VehicleCategory vc ON vc.VehicleCategoryId = o.VehicleCategoryId 
WHERE CAST(o.OrderTime AS date) = '2017-03-13' 
GROUP BY vc.VehicleCategoryName,o.OrderId

来源

2017-03-15 06:24:15 3rdEye

计算子查询select语句中的聚合值SQL

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