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我想这个查询转换中迅速:JSON查询与SWIFT,iOS的
<script>
jQuery.ajax(
{
url: "http://website.net/api/Clients/",
type: 'POST',
headers: {"Token": "Votre token"},
dataType: "json",
data: { "PhoneNumber": phoneNumberValue, "SecretCode": secretCodeValue },
success: function (data) { alert("it worked!") }
});
<script>
我在斯威夫特想这没有成功:
func submitNumber() {
let session = NSURLSession.sharedSession()
let url = NSURL(string: "http://website.net/api/Clients/")!
let request = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST”
request.allHTTPHeaderFields = ["Token" : “myKey”]
let requestDictionary = ["PhoneNumber": 3333333333, "SecretCode": 12345]
request.HTTPBody = try! NSJSONSerialization.dataWithJSONObject(requestDictionary, options: [])
let task = session.dataTaskWithRequest(request) { data, response, error in
if let httpResponse = response as? NSHTTPURLResponse {
let statusCode = httpResponse.statusCode
if (statusCode == 200) {
do {
let json = try NSJSONSerialization.JSONObjectWithData(data!, options:.AllowFragments)
print(json)
}catch {
print(error)
}
} else {
print(“failure”)
}
}
}
task.resume()
}
但它始终是印有 “失败”,我不知道如何处理它...
我该怎么办? 非常感谢!
如果问题是另一个问题的重复,那么您应该*将其标记为重复*而不是发布只是其他答案链接的答案。谢谢。 – Moritz
问题是不同的,但他需要的代码行是相同的。 – NSGangster
将问题标记为重复也适用于这种情况。 – Moritz