2017-10-10 69 views
0
df <- data.frame(id = c(1, 1, 1, 2, 2), 
       gender = c("Female", "Female", "Male", "Female", "Male"), 
       variant = c("a", "b", "c", "d", "e")) 
> df 
    id gender variant 
1 1 Female  a 
2 1 Female  b 
3 1 Male  c 
4 2 Female  d 
5 2 Male  e 

我想根据我的数据集中的gender列删除data.frame中的重复行。我知道有类似的问题提出(here),但这里的区别是我想删除数据集的每个子集中的重复行,其中每个子集都由唯一的id定义。R:如何按列删除重复行

我期望的结果是这样的:

id gender variant 
1 1 Female  a 
3 1 Male  c 
4 2 Female  d 
5 2 Male  e 

我试过以下,它的工作原理,但我不知道是否有这样做的更清洁,更有效的方式?

out = list() 
for(i in 1:2){ 
    df2 <- subset(df, id == i) 
    out[[i]] <- df2[!duplicated(df2$gender), ] 
} 
do.call(rbind.data.frame, out) 
+1

[使用dplyr删除重复行]可能的重复(https://stackoverflow.com/questions/22959635/remove-duplicated-rows-using-dplyr)或[使用ddply删除重复行](https:// stackoverflow .COM /问题/ 23079248 /删除重复的,行与 - ddply) –

回答

1
df[!duplicated(df[c("id","gender")]),] 

#  id gender variant 
# 1 1 Female  a 
# 3 1 Male  c 
# 4 2 Female  d 
# 5 2 Male  e 

这样做如下使用subset的另一种方式:

subset(df, !duplicated(subset(df, select=c(id, gender)))) 

# id gender variant 
# 1 1 Female  a 
# 3 1 Male  c 
# 4 2 Female  d 
# 5 2 Male  e 
0

这里是万一dplyr基础的解决方案,你有兴趣(编辑成包括Gregor的建议)

library(dplyr) 
group_by(df, id, gender) %>% slice(1) 

#> # A tibble: 4 x 3 
#> # Groups: id, gender [4] 
#>  id gender variant 
#> <dbl> <fctr> <fctr> 
#> 1  1 Female  a 
#> 2  1 Male  c 
#> 3  2 Female  d 
#> 4  2 Male  e 

也可能使用arrange函数以及取决于哪些值variant应该被删除。