C没有正确地看到我的功能？

Question

进出口新的C.我有一个函数定义为这样：

/* 
* Draws an image in mode3 USING DMA. 
* int x x coordinate 
* int y y coordinate 
* int width Width of the image (Note may not be the same width as the GBA) 
* int height Height of the image (Note may not be the same height as the GBA) 
* const u16* pointer to the first element in the image 
*/ 
void drawImage3(int x, int y, int width, int height, const u16* image) 
{ 
    int r; 
    for (r=0; r<height; r++) { 

      DMA[3].src = &image; 
      DMA[3].dst = &videoBuffer[OFFSET(x+width, y, 240)]; 
      DMA[3].cnt = width | DMA_SOURCE_FIXED| DMA_ON | DMA_DESTINATION_INCREMENT; 
      image = &image + (r * width); 

    } 

} 

在.h文件I包括在我的主程序我有这样的：

void drawImage3(int x, int y, int width, int height, const u16* image); 

其中U16是指无符号短并在其他地方定义。

而这些，也都在我的.h文件：

extern unsigned short *videoBuffer; 
extern const unsigned short *pt; 

在另一个.h文件

是1024 const的无符号短数组。

在我的main.c文件，我打电话给我的功能是这样的：

pt = imgArray; 
drawImage3(25,25, img_WIDTH, img_HEIGHT, pt); 

我得到了很多的错误。

Program.c:22: error: data definition has no type or storage class 
Program.c:22: error: type defaults to 'int' in declaration of 'pt' 
Program.c:22: error: conflicting types for 'pt' 
myLib.h:21: note: previous declaration of 'pt' was here 
Program.c:22: error: initializer element is not constant 
Program.c:23: error: expected declaration specifiers or '...' before numeric constant 
Program.c:23: error: expected declaration specifiers or '...' before numeric constant 
Program.c:23: error: expected declaration specifiers or '...' before numeric constant 
Program.c:23: error: expected declaration specifiers or '...' before numeric constant 
Program.c:23: error: expected declaration specifiers or '...' before 'pt' 
Program.c:23: error: data definition has no type or storage class 
Program.c:23: error: type defaults to 'int' in declaration of 'drawImage3' 
Program.c:23: error: conflicting types for 'drawImage3' 
myLib.h:117: note: previous declaration of 'drawImage3' was here 

任何有关这里发生了什么的想法？

-------编辑

是，奥利，你说得对第一个错误。谢谢！我编辑了我的函数，并且错误消失了。我也做了我的* pt和extern。

Program.c：

//Philip Johnson 
#include <stdio.h> 
#include "img.h" 
#include <unistd.h> 
#include "myLib.h" 
#include "text.h" 

typedef struct  // This typedef defines a new type called MOVOBJ 
{      // which are structures that hold all the info for 
    int row;   // a single movable object 
    int col; 
    int rdel; 
    int cdel; 
    u16 color; 

} MOVOBJ; 

MOVOBJ newcharacter, car1, car2, car3; 
int size = 5; 
int speed = 2; 
int checkforend = 0; 
pt = imgArray; 
drawImage3(25,25, img_WIDTH, img_HEIGHT, pt); 
int main(){ //....and so on from there 

Answer 1

你大概的意思u16* pt = imgArray; - 如果你用C宣布新的变量你必须给的类型。