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我在写一个C++项目，我想将其转换为汇编代码。虽然我研究了这个特定的错误，但没有一个给出的答案似乎解决了我的问题。这里是代码：体系结构x86_64的未定义符号：C++项目
//
// main.cpp
// TicTacToe
//
//
//
#include <iostream>
void printboard(char board[][3]);
void update(char board[][3],char,int,int);
bool isValid(char board[][3],char,int,int);
int menu();
void game1(char board[][3]);
void game2(char board[][3]);
void game3(char board[][3]);
void game4(char board[][3]);
void def();
bool state(char board[][3],int,int);
using namespace std;
int main(int argc, const char * argv[]) {
//game board, initialize with 0's
char board[3][3] = {{'0','0','0'},{'0','0','0'},{'0','0','0'}};
int choice = menu();
switch(choice)
{
case 1: game1(board);break;
case 2: game2(board);break;
case 3: game3(board);break;
case 4: game4(board);break;
default: def();break;
}
return 0;
}
int menu()
{
int temp;
cout<<"Welcome to Tic-Tac-Toe. Please enter a mode in which to play.\n";
cout<<"Enter 1 to choose to play against another opponent.\n";
cout<<"Enter 2 to play against easy AI.\n";
cout<<"Press 3 to play against medium AI.\n";
cout<<"Press 4 to play against hard AI.\n";
cin>>temp;
return temp;
}
void update(char board[][3],char choice,int i,int j)
{
toupper(choice);
if(choice == 'O'){
board[i][j] = 'O';
}else{
board[i][j] = 'X';
}
}
void printboard(char board[][3])
{
for(int i=0;i<3;i++){
for(int j=0;j<3;j++){
cout<<board[i][j]<<"|";
}
cout<<endl;
cout<<"______"<<endl;
}
}
void def()
{
cout<<"Invalid choice. Enter numbers 1-4.\n";
}
bool isValid(int board[3][3],char choice,int row,int col)
{
toupper(choice);
if(row >= 3 || col >=3)
return false;
if(choice != 'O' || choice != 'X')
return false;
if(board[row][col] == 'O' || board[row][col] == 'X')
return false;
return true;
}
bool state(char board[][3],int choice1,int choice2)
{
//check for win state, these are absolutes
if((board[0][2] == choice1 && board[1][1] == choice1 && board[0][2] == choice1))
{
cout<<"Player 1 wins!!!\n";
return false;
}
else if(board[0][2] == choice2 && board[1][1] == choice2 && board[0][2] == choice2){
cout<<"Player 2 wins!!!\n";
return false;
}
if(board[0][0] == choice1 && board[1][1] == choice1 && board[2][2] == choice1){
cout<<"Player 1 wins!!!\n";
return false;
}
else if(board[0][0] == choice2 && board[1][1] == choice2 && board[2][2] == choice2){
cout<<"Player 2 wins!!!\n";
return false;
}
if(board[0][0] == choice1 && board[1][0] == choice1 && board[2][0] == choice1){
cout<<"Player 1 wins!!!\n";
return false;
}
else if(board[0][0] == choice2 && board[1][0] == choice2 && board[2][0] == choice2){
cout<<"Player 2 wins!!!\n";
return false;
}
if(board[0][0] == choice1 && board[0][1] == choice1 && board[0][2] == choice1){
cout<<"Player 1 wins!!!\n";
return false;
}
else if(board[0][0] == choice2 && board[0][1] == choice2 && board[0][2] == choice2){
cout<<"Player 2 wins!!!\n";
return false;
}
if(board[0][2] == choice1 && board[1][2] == choice1 && board[2][2] == choice1){
cout<<"Player 1 wins!!!\n";
return false;
}
else if(board[0][2] == choice2 && board[1][2] == choice2 && board[2][2] == choice2){
cout<<"Player 2 wins!!!\n";
return false;
}
if(board[1][0] == choice1 && board[1][1] == choice1 && board[1][2] == choice1){
cout<<"Player 1 wins!!!\n";
return false;
}
else if(board[1][0] == choice2 && board[1][1] == choice2 && board[1][2] == choice2){
cout<<"Player 2 wins!!!\n";
return false;
}
if(board[2][0] == choice1 && board[2][1] == choice1 && board[2][2] == choice1){
cout<<"Player 1 wins!!!\n";
return false;
}
else if(board[2][0] == choice2 && board[2][1] == choice2 && board[2][2] == choice2){
cout<<"Player 2 wins!!!\n";
return false;
}
return true;
}
void game1(char board[][3])
{
char choice1;
char choice2;
int row;
int col;
bool gamestate;
bool valid;
cout<<"Player 1, would you like to be X or O?\n";
cin>>choice1;
cout<<"Player 2, would you like to be X or O?\n";
cin>>choice2;
do{
do{
//Get players intput and check if the input is valid
cout<<"Player 1, enter row/col to place your move.\n";
cin>>row>>col;
valid = isValid(board,choice1,row,col);
cout<<"Player 2, enter row/col to place your move.\n";
cin>>row>>col;
valid = isValid(board,choice2,row,col);
}while(valid);
//check the state of the game
gamestate = state(board,choice1,choice2);
}while(gamestate);
}
void game2(char board[][3])
{
cout<<"In game 2"<<endl;
}
void game3(char board[][3])
{
cout<<"In game 3"<<endl;
}
void game4(char board[][3])
{
cout<<"In game 4"<<endl;
}
这是Xcode输出的错误。它指出问题是函数IsValid。虽然我似乎正在传递数组，并且正确定义了原型。我不知道这里发生了什么。
Ld /Users/justinfulkerson/Library/Developer/Xcode/DerivedData/TicTacToe-fioiynyiwrhpecfdznfogllqdmvx/Build/Products/Debug/TicTacToe normal x86_64
cd /Users/justinfulkerson/dev/CSC11/FulkersonJustinCSC11/Project/TicTacToe
export MACOSX_DEPLOYMENT_TARGET=10.10
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang++ -arch x86_64 -isysroot /Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.11.sdk -L/Users/justinfulkerson/Library/Developer/Xcode/DerivedData/TicTacToe-fioiynyiwrhpecfdznfogllqdmvx/Build/Products/Debug -F/Users/justinfulkerson/Library/Developer/Xcode/DerivedData/TicTacToe-fioiynyiwrhpecfdznfogllqdmvx/Build/Products/Debug -filelist /Users/justinfulkerson/Library/Developer/Xcode/DerivedData/TicTacToe-fioiynyiwrhpecfdznfogllqdmvx/Build/Intermediates/TicTacToe.build/Debug/TicTacToe.build/Objects-normal/x86_64/TicTacToe.LinkFileList -mmacosx-version-min=10.10 -stdlib=libc++ -Xlinker -dependency_info -Xlinker /Users/justinfulkerson/Library/Developer/Xcode/DerivedData/TicTacToe-fioiynyiwrhpecfdznfogllqdmvx/Build/Intermediates/TicTacToe.build/Debug/TicTacToe.build/Objects-normal/x86_64/TicTacToe_dependency_info.dat -o /Users/justinfulkerson/Library/Developer/Xcode/DerivedData/TicTacToe-fioiynyiwrhpecfdznfogllqdmvx/Build/Products/Debug/TicTacToe
Undefined symbols for architecture x86_64:
"isValid(char (*) [3], char, int, int)", referenced from:
game1(char (*) [3]) in main.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
您声明'isValid'与第一个参数为'的char [] [3]'与'字符定义它[3] [3]'：不同的签名。 – Kenney
@Kennyey。喔好吧。我只是解决了这个问题，但它仍然失败并出现相同的错误。 –