算括号内的数字字符串中的

Question

我有一个像下面

*WTY: but the light of the dining room suddenly turn off . 
%mor: conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off . 
%snd: <00:14:74><00:25:53> 
%WTY: {and} rpl but {suddenly} rpl (0.43) {the} * (1.07) {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: | 

我想提取圆括号内的数字（），并计算这些数字的总和一个特定的字符串。 我已经尝试过以下RegEx提取数字，但它没有返回任何结果。

str.match(/\((\d+)\)/) 

Answer 1

你可以试试这个：

/\((\d*\.?\d*)\)/g 

Explanation

const regex = /\((\d*\.?\d*)\)/g; 
 
const str = `*WTY: but the light of the dining room suddenly turn off . 
 
%mor: conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off . 
 
%snd: <00:14:74><00:25:53> 
 
%WTY: {and} rpl but {suddenly} rpl (0.43) {the} * (1.07) {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: |`; 
 
let m; 
 

 
var val=0.0; 
 
while ((m = regex.exec(str)) !== null) { 
 
    if (m.index === regex.lastIndex) { 
 
     regex.lastIndex++; 
 
    } 
 
    //console.log(m[1]); 
 
    val+=parseFloat(m[1]); 
 
} 
 
console.log(val);

为了弥补您的评论在接受的答案

还有一件事情，如果我只需要计算在：：（包括：;：a，：;：b，：;：a）之前或之后的括号 的和即可。

你可以应用这个表达式：

:;:\s*\((\d*\.?\d*)\)|\((\d*\.?\d*)\)\s*:;: 

const regex = /:;:\s*\((\d*\.?\d*)\)|\((\d*\.?\d*)\)\s*:;:/g; 
 
const str = `*WTY: but the light of the dining room suddenly turn off . 
 
%mor: conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off . 
 
%snd: <00:14:74><00:25:53> 
 
%WTY: {and} rpl but {suddenly} rpl :;: (0.43) {the} * (1.07) :;: {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: |`; 
 
let m; 
 

 
var val=0.0; 
 
while ((m = regex.exec(str)) !== null) { 
 
    if (m.index === regex.lastIndex) { 
 
     regex.lastIndex++; 
 
    } 
 
    if(typeof m[1] !== 'undefined') 
 
    val+=parseFloat(m[1]); 
 
    else 
 
    val+=parseFloat(m[2]); 
 
    //val+=parseFloat(m[1]); 
 
} 
 
console.log(val);

Answer 2

你有没有结果的主要原因是，你不占数量的点，所以你会错过所有的非整数。一旦你改正了，你仍然只会得到一个结果，因为你没有在你的正则表达式中指定全局修饰符（g）。

您可以使用此三步转换：

const sum = s.match(/\([\d.]+(?=\))/g) // get the numbers 
      .map(a => +a.substr(1)) // remove opening parenthesis and convert to number 
      .reduce((a,b) => a+b); // total them 

演示：

const s = `*WTY: but the light of the dining room suddenly turn off . 
 
%mor: conj|but det|the n|light prep|of det|the adj|dining n|room adv|suddenly v|turn adv|off . 
 
%snd: <00:14:74><00:25:53> 
 
%WTY: {and} rpl but {suddenly} rpl (0.43) {the} * (1.07) {the light (0.78) suddenly turn off and} # (1.24) the light of the dining room suddenly turn off . err_m_s err_m_l ::: |`; 
 

 
const sum = s.match(/\([\d.]+(?=\))/g) // get the numbers 
 
      .map(a => +a.substr(1)) // remove opening parenthesis and convert to number 
 
      .reduce((a,b) => a+b); // total them 
 

 
console.log(sum.toFixed(2));

注：调用.toFixed是可选的，但它解决了一个问题，你可能会得到floating point inaccuracies。