GROUP BY的COUNT（*）

我有一个查询返回644行，按几列分组。我需要得到这些行的计数，644GROUP BY的COUNT（*）

这是查询：

SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count] 
FROM HeadOffice ho INNER JOIN Properties ON Properties.head_office_code = ho.id 
WHERE Somecondition 
GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status

尽管试图COUNT(*)，在另一个查询包裹，并取出GROUP BY，我不能让“644”背部。我最近来的是644行，全都包含'1'。这可能吗？

来源

2012-01-09 Echilon

'select count（1）from（select distinct ID， honame，来自HeadOffice的ho_status）忽略'return？ – dasblinkenlight 2012-01-09 16:03:26

如果您的原始查询返回正确的行数，您为什么要在从（<您的原始查询>）中选择计数（*）时进行更改？ – JeffO 2012-01-09 16:15:24

最简单的方式做到这一点正是如此：

SELECT count(1) as NumRows from 
(SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count] 
FROM HeadOffice ho INNER JOIN Properties ON clients.head_office_code = ho.id 
WHERE Somecondition 
GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status) x

如果你想计数加你的专栏，使用over：

SELECT 
    count(1) over() as NumRows, 
    x.ID, 
    x.ho_status, 
    x.[sales value], 
    x.[property count] 
from 
(SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count] 
FROM HeadOffice ho INNER JOIN Properties ON clients.head_office_code = ho.id 
WHERE Somecondition 
GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status) x

来源

2012-01-09 16:00:28 Eric

我正在做COUNT（*）从上面，但这完美的作品。谢谢。 – Echilon 2012-01-09 16:12:33

您将得到1个更多的行到您的列表中，其中包含属性数量和属性值的所有内容的空值。该记录将具有计数和所有属性值的总和。

SELECT DISTINCT ho.ID,ho.honame,ho.ho_status, 
SUM(Properties.Value) as [sales value], 
COUNT(Properties.record_id) as [property count] 
FROM HeadOffice ho 
INNER JOIN Properties 
    ON clients.head_office_code = ho.id 
WHERE Somecondition 
GROUP BY Grouping sets((ho.ID,ho.honame,ho_status),()) 
ORDER BY ho_status

来源

2012-01-09 15:58:10 xQbert

这应该工作

SELECT COUNT(ID) 
FROM (
SELECT DISTINCT ho.ID,ho.honame,ho.ho_status, 
     SUM(Properties.Value) as [sales value], 
     COUNT(Properties.record_id) as [property count] 
FROM HeadOffice ho 
    INNER JOIN Properties ON clients.head_office_code = ho.id 
WHERE Somecondition 
GROUP BY ho.ID, ho.honame, ho_status) t

来源

2012-01-09 15:59:38

GROUP BY的COUNT（*）

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