我正在练习Java swing。我创建了一个矩阵作为Rectangle2D
对象的二维数组。我已经设置了MouseListener
来绘制被点击的方块。我已经设置了用于检查哪个方块被点击的for循环。当我点击一个正方形时,它被涂成蓝色。事情是,当我点击另一个广场时,第一个变成白色,另一个变成蓝色。我的问题是,如何保持第一次点击广场的颜色?在Java中绘制方形矩阵
这里的Matrica(Matrix)
类(这是我的母语的代码,crtanjeMatrice
意味着drawMatrix
和duzina
是length
public class Matrica extends JPanel implements MouseListener {
Rectangle2D[][] matrica = new Rectangle2D[8][8];
Color boja = Color.white;
int a = 0;
int b = 0;
public Matrica() {
addMouseListener(this);
}
public void paint(Graphics g){
Graphics2D g2 = (Graphics2D)g;
g2.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON);
g2.clearRect(0, 0, this.getWidth(), this.getHeight());
crtanjeMatrice(g2);
g2.setColor(boja);
g2.fill(matrica[a][b]);
}
private void crtanjeMatrice(Graphics2D g2){
g2.setColor(Color.black);
int startX = 0;
int startY =0;
int duzina = 50;
for(int i=0; i < matrica.length; i++){
for(int j = 0; j < matrica.length; j++){
matrica[i][j] = new Rectangle2D.Double(startX,startY,duzina,duzina);
g2.draw(matrica[i][j]);
startX = startX + duzina;
}
startY = startY + duzina;
startX = 0;
}
}
@Override
public void mouseClicked(MouseEvent e) {
}
@Override
public void mousePressed(MouseEvent e) {
int m,n;
int x = e.getX();
int y = e.getY();
for(int i = 0; i < matrica.length; i++)
for(int j =0; j < matrica.length; j++)
if(matrica[i][j].contains(x, y)){
boja = Color.blue;
a = i;
b = j;
repaint();
}
}
@Override
public void mouseReleased(MouseEvent e) {
}
@Override
public void mouseEntered(MouseEvent e) {
}
@Override
public void mouseExited(MouseEvent e) {
}
}
你可以发布你的代码的相关部分? – MAK
你可以显示一些代码吗?否则,解决方案是将点击时的颜色存储到临时变量中。 –