初始化期间python继承函数覆盖

Question

不知何故，Father类可以看到Child类的方法。我推测只有内部方法可用于父亲初始

但显然我错了。下面是代码：

class Father(): 
    def __init__(self): 
     self.name=self.getName() 
     print "from Father ->", self.name 

    def getName(self): 
     return "father" 

class Child(Father): 
    def __init__(self):   
     Father.__init__(self) 
     self.name=self.getName() 
     print "from Child ->", self.name 

    def getName(self): 
     return "child" 

if __name__ == "__main__": 
    import sys, pprint 

    someone=Child() 

，输出是

from Father -> child 
from Child -> child 

但我想获得

from Father -> father 
from Child -> child 

任何思考如何改写呢？ Tnx！

Answer 1

这是name-mangling目的：它可以让你说： “这个类的属性”：

class Father(): 
    def __init__(self): 
     self.name=self.__getName() 
     print "from Father ->", self.name 
    def __getName(self): 
     return "father" 

class Child(Father): 
    def __init__(self):   
     Father.__init__(self) 
     self.name=self.__getName() 
     print "from Child ->", self.name 

    def __getName(self): 
     return "child" 

if __name__ == "__main__": 
    import sys, pprint 

    someone=Child() 

产量

from Father -> father 
from Child -> child 

欲了解更多信息，请参见也this post。