我的程序已启动并正在运行,但是我的if语句出现问题,导致“scalene”成为除正确输出之外的输出(除非scalene是正确的输出)。看看这个问题:如果声明有问题?
任何人都可以发现的bug?
triangleShape功能
# include "header.h"
triangleType triangleShape(float sideLength1, float sideLength2, float sideLength3)
{
triangleType triangle;
if (sideLength1 + sideLength2 < sideLength3)
triangle = noTriangle;
else if (sideLength1 + sideLength3 < sideLength2)
triangle = noTriangle;
else if (sideLength3 + sideLength2 < sideLength1)
triangle = noTriangle;
else if (sideLength1 == sideLength2 == sideLength3)
triangle = equilateral;
else if (sideLength1 == sideLength2)
triangle = isoceles;
else if (sideLength1 == sideLength3)
triangle = isoceles;
else if (sideLength2 == sideLength3)
triangle = isoceles;
else
triangle = scalene;
return triangle;
}
输出功能
# include "header.h"
void output (float sideLength1, float sideLength2, float sideLength3)
{
if (triangleShape (sideLength1, sideLength2, sideLength3) == noTriangle)
cout << "Side lenghts of " << sideLength1 << " " << sideLength2 << " and " << sideLength3 << " would not form a triangle." << endl;
else if (triangleShape (sideLength1, sideLength2, sideLength3) == equilateral)
cout << "A triangle with sides of lengths " << sideLength1 << " " << sideLength2 << " and " << sideLength3 << "would be " <<
"an equilateral triangle."<< endl;
else if (triangleShape (sideLength1, sideLength2, sideLength3) == isoceles)
cout << "A triangle with sides of lengths " << sideLength1 << " " << sideLength2 << " and " << sideLength3 << "would be " <<
"an isoceles triangle."<< endl;
else (triangleShape (sideLength1, sideLength2, sideLength3) == scalene);
cout << "A triangle with sides of lengths " << sideLength1 << " " << sideLength2 << " and " << sideLength3 << " would be " <<
"a scalene triangle."<< endl;
}
在相关说明中,我建议您使用`switch` /`case`构造或查找表来避免所有这些`if',这将使代码更具可读性并避免这种错误。 – 2011-02-06 01:09:42
除了任何其他问题,比较`if(sideLength1 == sideLength2 == sideLength3)`不会做你认为的事情。 – Blastfurnace 2011-02-06 01:11:49