填充多维数组

Question

以下代码作为包含文件，包含我正在处理的初学者拼图应用教程。该代码的作品，但是现在，我已经完成了教程，我试图通读未预先解释的预加载的文件。

我真的绊倒了“spacecount”变量，它究竟在做什么。任何人都可以用纯英文评论每一行，这样我可以更好地理解下面的代码是如何填充rowCount数组的。非常感谢。

var totalRows = puzzle.length; 
var totalCols = puzzle[0].length; 

/* Loop through the rows to create the rowCount array 
containing the totals for each row in the puzzle */ 

var rowCount = []; 
for (var i = 0; i < totalRows; i++) { 
    rowCount[i]=""; 
    spaceCount = 0; 

    for (var j = 0; j < totalCols; j++) { 
    if (puzzle[i][j] == "#") { 
     spaceCount++; 

     if (j == totalCols-1) rowCount[i] += spaceCount + "&nbsp;&nbsp;"; 
     } else { 
      if (spaceCount > 0) { 
      rowCount[i] += spaceCount + "&nbsp;&nbsp;"; 
      spaceCount = 0; 
     } 
     }  
    } 

Answer 1

这里有一个稍微清晰的版本：

var totalRows = puzzle.length; 
var totalCols = puzzle[0].length; 

/* Loop through the rows to create the rowCount array 
containing the totals for each row in the puzzle */ 

var rowCount = []; 

for (var i = 0; i < totalRows; i++) { 
    rowCount[i] = ""; 
    spaceCount = 0; 

    for (var j = 0; j < totalCols; j++) { 
     if (puzzle[i][j] == "#") { 
      spaceCount++; 

      if (j == totalCols - 1) { 
       rowCount[i] += spaceCount + "&nbsp;&nbsp;"; 
      } 
     } else if (spaceCount > 0) { 
      rowCount[i] += spaceCount + "&nbsp;&nbsp;"; 
      spaceCount = 0; 
     } 
    } 
}​ 

混乱的部分可能是中间的if块。

if (puzzle[i][j] == "#") {  // If a puzzle piece is `#` (a space?) 
    spaceCount++;    // Increment the spaceCount by 1. 

    if (j == totalCols - 1) { // Only if we are on the last column, add the text 
           // to the row. 
     rowCount[i] += spaceCount + "  "; 
    } 
} else if (spaceCount > 0) { // If the current piece isn't a `#` but 
           // spaces have already been counted, 
           // add them to the row's text and reset `spaceCount` 
    rowCount[i] += spaceCount + "  "; 
    spaceCount = 0; 
}​ 

从我所知道的情况来看，这段代码计算连续井号的数量，并将这段文字追加到每一行。