派生抽象类我有两个类这样惩戒从抽象类
public abstract class Foo<T> where T : Bar {
public Bar Do(Bar obj) {
//I cast to T here and the call the protected one.
}
...
protected abstract Bar Do(T obj);
}
public abstract class FooWithGoo<T> : Foo<T> where T:Bar {
...
}
试图使用Moq的这一行new Mock<FooWithGoo<Bar>>()
一个单元测试嘲笑这给了我此异常。
System.ArgumentException: Type to mock must be an interface or an abstract or non-sealed class. ---> System.TypeLoadException: Method 'Do' in type 'Castle.Proxies.FooWithGoo``1Proxy' from assembly 'DynamicProxyGenAssembly2, Version=0.0.0.0, Culture=neutral, PublicKeyToken=null' does not have an implementation.
有什么我做错了吗?我怎么嘲笑这个?
更新: 这显示了对我来说很好的问题。
using Microsoft.VisualStudio.TestTools.UnitTesting;
using Moq;
namespace UnitTestProject1
{
public class Bar
{
}
public class BarSub : Bar
{
}
public abstract class Foo<T> where T : Bar
{
public Bar Do(Bar obj)
{
return null;
}
protected abstract Bar Do(T obj);
}
public abstract class FooWithGoo<T> : Foo<T> where T : Bar
{
public FooWithGoo(string x)
{
}
}
[TestClass]
public class UnitTest1
{
[TestMethod]
public void TestMethod1()
{
var mock = new Mock<FooWithGoo<Bar>>("abc");
FooWithGoo<Bar> foo = mock.Object;
}
[TestMethod]
public void TestMethod2()
{
var mock = new Mock<FooWithGoo<BarSub>>("abc");
FooWithGoo<BarSub> foo = mock.Object;
}
}
}
测试2通过时Test1失败。 问题是通用抽象比具体方法获得相同的签名......并且它被我猜测弄糊涂了。
我现在可以重现这一点。你的猜测对我来说听起来很合理 – tster