使得路由器需要帮助搞清楚为什么我得到403

Question

抱歉，我不能想出一个更好的解释短标题

我有一个小网站，IM使这个简单的路由器。

如果request_uri中有一个点，它将退出，停止breakout。但是当我尝试一个网址，我得到403在我自己的服务器上

为什么要得到403？我strpos应该抓住这一

$request = $_SERVER['REQUEST_URI']; 
$params = explode('/', $request); 

if (strpos($request, '.') !== false) { 
//breakout attempt 
} 

if (!file_exists(sprintf('pages/%s.php', $params[1]))) { 
//requested page does not exists, throw or display error 
    error(); 
} else { 
    include sprintf('pages/%s.php', $params[1]); 
} 

现在这个捕获的URL像

http://localhost/asfasg/asfass.sg 
http://localhost/www.hello.se 
http://localhost/asfasg/dsgsdg/fas.asgas 

但

http://localhost/https://www.youtube.com/watch?v=j1w87N9MLhM 
http://localhost/banana://ww.sdf.xx/saf 

好像如果有something:在请求URI

You don't have permission to access /https://www.youtube.com/watch on this server. 
Apache/2.4.9 (Win64) PHP/7.0.2RC1 Server at localhost Port 80 

为什么？

Answer 1

$request = "http://localhost/https://www.youtube.com/watch?v=j1w87N9MLhM"; 
$params = explode('/', $request); 

//you want the last index which should be the filename 
$filename = array_pop($params); 

if (strpos($filename, '.') !== false) { 
//breakout attempt 
} 

if (!file_exists(sprintf('pages/%s.php', $filename))) { 
//requested page does not exists, throw or display error 
    error(); 
} else { 
    include sprintf('pages/%s.php', $filename); 
}