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我正在传递用户从他们的计算机或手机上传的照片。上传来自用户输入的图像,传递给ajax,并返回带有响应的图像
HTML:
<input class="button" type="file" capture="camera" accept="image/*" id="upload-button" name="cameraInput">
我得到的图像,并将其传递给我的AJAX调用,以便将其发送到API。我想只通过原始图像上载,但我总是和错误: “coyote1.jpg:1个GET MYAPP.com/coyote1.jpg网:: ERR_FILE_NOT_FOUND”
的jQuery:
var uploadImage = function() {
var uploadBtn = $('#upload-button');
uploadBtn.change(function(event) {
var formData = new FormData();
var file = event.target.files[0];
formData.append('sampleContent', file);$.ajax({
url: 'MY API ENPOINT,
method: 'POST',
headers: {
'Access-Control-Allow-Origin': '*',
'Authorization':
'Bearer <MY TOKEN>',
'Cache-Control': 'no-cache'
},
data: formData,
processData: false,
contentType: false
}).done(function(res) {
var introArticle = $('#intro');
var htmlCard = introArticle.append($(`<div class="card" </div>`));
var htmlContainer = htmlCard.append($(`<div class="container"></div>`));
var htmlImage = htmlCard.append($(`<img src="${file.name}")}" style="width:100%"/>`));
)};
它试图从我的应用程序中查看照片,但它来自用户。我如何将它指引到照片的正确路径?
十分感谢,这完美! – cal