0
在此先感谢。当我为这个数组输入一个最小值时,我无法弄清楚为什么我的代码会给我带来麻烦。它似乎保留最初的0值,但我不知道如何解决这个问题。 Max工作正常。我是否在程序的错误部分设置了最大值和最小值?另外,这是我对数组的第一次任务,所以我可能在稍后打印下标时遇到一些问题。数组返回0的最小值(目标是查找最大值和最小值)
再次感谢!
编辑 - 这就解决了这个问题,据我所知。感谢丹W.
for (int i = 0; i < NUMBER_OF_ELEMENTS; i++) {
System.out.print("Enter a new number. This will continue until "
+ "you reach the size of the array. ");
arrayOfNumbers[i] = keyboard.nextInt();
}
int max = arrayOfNumbers[0];
int min = arrayOfNumbers[0];
package program8;
import java.util.Scanner;
public class arrayPrint {
public static void main(String[] args) {
final int NUMBER_OF_ELEMENTS;
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter the amount of numbers the array will read in. ");
NUMBER_OF_ELEMENTS = keyboard.nextInt();
int arrayOfNumbers[] = new int[NUMBER_OF_ELEMENTS];
int max = arrayOfNumbers[0];
int min = arrayOfNumbers[0];
for (int i = 0; i < NUMBER_OF_ELEMENTS; i++) {
System.out.print("Enter a new number. This will continue until "
+ "you reach the size of the array. ");
arrayOfNumbers[i] = keyboard.nextInt();
}
for (int i = 0; i < arrayOfNumbers.length; i++) {
if (max <= arrayOfNumbers[i])
max = arrayOfNumbers[i];
}
for (int i = 0; i < arrayOfNumbers.length; i++) {
if (min >= arrayOfNumbers[i])
min = arrayOfNumbers[i];
}
System.out.print(+max+ "max and " +min+ " min");
}
}
像上面那样? (我不知道如何在评论中放置代码,但它没有看起来很糟糕,所以它在编辑中,在原始代码之上。我是这样工作的。我之前已经尝试过,但它没有工作,因为我在它之内第一个for循环的括号,谢谢!看起来是否正确? – user1082706
是的,我当时只输入正数,谢谢 – user1082706
是的,这看起来不错,希望它可以工作,请接受答案,如果这解决了您的问题 –