TypeError：'int'对象不可调用Python 3

Question

好的，所以，我试图做一个“猜数字”游戏，一个游戏，你说一个数字，另一个玩家说“下”或“更高“取决于你的答案，并且当你正确地猜出你的号码时，你就赢了。

也许这已经回答了，但我无法弄清楚什么是错的。

我不明白，如果在你自己调用的函数内，它应该再次运行自己，对吧？

不知道是否有帮助，但我使用Python 3

number = 897 
attempts = 0 

def guess(): 
    guess = input("Number: ") 
    guess = int(guess) 
    global attempts 
    if guess > number: 
     print("It's lower.") 
     attempts = attempts + 1 
     guess() 
    elif guess < number: 
     print("It's higher.") 
     attempts = attempts + 1 
     guess() 
    else: 
     print("Correct! The number was " + str(number) + "!") 
     print("It took you " + str(attempts) + "!"), 

print("I'm thinking of a number, guess it!") 
guess() 

Answer 1

.... 

def guess():     # guess is a function 
    guess = input("Number: ") 
    guess = int(guess)   # it's become int now 
    global attempts 
    if guess > number: 
     print("It's lower.") 
     attempts = attempts + 1 
     guess()     # you're trying to call an int object, because you defined it as a int object as I said. 

.... 

所以，请改变你的函数名或变量名。

Answer 2

变量名称与函数名称相同。您忘记了在正确的猜测字符串处添加“尝试”。

number = 897 
attempts = 0 

def guess1(): 
    guess = input("Number: ") 
    guess = int(guess) 
    global attempts 
    if guess > number: 
     print("It's lower.") 
     attempts = attempts + 1 
     guess1() 
    elif guess < number: 
     print("It's higher.") 
     attempts = attempts + 1 
     guess1() 
    else: 
     print("Correct! The number was " + str(number) + "!") 
     print("It took you " + str(attempts) + " attempts !"), 

print("I'm thinking of a number, guess it!") 
guess1()