2012-05-11 27 views

回答

5

一个quick search想出了这一点:

SELECT LENGTH('/2323/3235/4545/222/') - LENGTH(REPLACE('/2323/3235/4545/222/','/','')) ... etc; 
+1

+1,那么容易,我怎么能忘了这 –

3

link

SELECT LENGTH('/2323/3235/4545/222/') - LENGTH(REPLACE('/2323/3235/4545/222/', '/', '')) AS `occurrences` 
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