我试图深入到一个嵌套的JSon数组,我已经成功地完成了上面的级别,但我不能解决如何获得更深入的。NSJSONSerialization Json嵌套Sub
我需要登录图片@url我附上了一个屏幕显示,以显示我需要它去的地方。
谢谢:)
- (void)viewDidLoad
{
[super viewDidLoad];
[UIApplication sharedApplication].networkActivityIndicatorVisible = YES;
NSURL *url = [NSURL URLWithString:@"http://api.storageroomapp.com/accounts/511a4f810f66026b640007b8/collections/511a51580f66023bff000ce9/entries.json?auth_token=Zty6nKsFyqpy7Yp5DP1L&preview_api=1"];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
[[NSURLConnection alloc] initWithRequest:request delegate:self];
}
-(void)connectionDidFinishLoading:(NSURLConnection *) connection{
[UIApplication sharedApplication].networkActivityIndicatorVisible = NO;
NSDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:data options:nil error:nil];
NSDictionary *arrayDictionary = dictionary[@"array"];
news = arrayDictionary[@"resources"];
[tableView reloadData];
}
-(void) connection:(NSURLConnection *)connection didFailWithError:(NSError *)error{
UIAlertView *errorView = [[UIAlertView alloc] initWithTitle:@"Error" message:@"The data could not be downloaded - please make sure you're connected to either 3G or Wi-FI" delegate:nil cancelButtonTitle:@"Dismiss" otherButtonTitles:nil];
[errorView show];
[UIApplication sharedApplication].networkActivityIndicatorVisible = NO;
}
-(int)numberOfSectionsInTableView:(UITableView *)tableView{
return 1;
}
-(int)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section{
return [news count];
}
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath{
NSDictionary *newsItem = news[[indexPath row]];
NSString *title = newsItem[@"title"];
NSString *date = newsItem[@"date"];
NSString *thumb = newsItem[@"tablethumb"];
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"MainCell"];
if (cell == nil) {
cell = [[UITableViewCell alloc]initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:@"MainCell"];
[[cell textLabel] setText:title];
[[cell detailTextLabel] setText:date];
if((NSNull *)thumb == [NSNull null]){
NSLog(@"no image");
} else{
NSLog(@ "image = %@", thumb);
}
}
cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
return cell;
}
感谢您的快速回应,我试过上面的代码和我的控制台说。 image =(null),然后我尝试@“tablethumb。@ url”,并在NSUnkownKeyException的最后一个日志中出现错误。 – Brent 2013-02-22 11:44:17
是的,只是意识到你有实际的'@'作为前缀。请参阅我的编辑答案 – Alladinian 2013-02-22 11:48:04
@BrentFrench另请注意,在您的代码中,您将'tablethumb'视为字符串,而在您的json中将其视为字典... – Alladinian 2013-02-22 11:51:20