Question

我知道有些帖子几乎与我通过其中很多人看过的内容几乎相同，但可悲的是还没有找到解决方案。我的问题是我写了一个电子邮件valiadtor使用jQuery的.addmethod（）函数jQuery验证插件。

$.validator.addMethod("uniqueEmail", function(value, element) { 
    $.ajax({ 
     data: 'email=' + value, 
     type: 'get', 
     url: 'functions/emailcheck.php', 
      dataType:"html", 
      success: function(msg) { 
       alert("M:"+msg+" V:"+value); 
       if(msg == true || msg != null || msg == "true"){ 
        return true; 
        alert("TRUE!!!"); 
       } 
       else{ 
        return false; 
       } 
      } 
     }); 
    }); 

在验证规则

则...

email: { required: true, email: true, uniqueEmail: true }, 

后来终于即使在这个PHP文件....

<?php 
    echo "true"; 
?> 

它给我的警告，真实已是注册，邮件中有邮件.. uniqueEmail: jQuery.format("{0} has already been registered")。现在我有一个调试警报设置int他ajax调用。它显示它返回true，并且该值与输入一样。

我希望有一些帮助，这会让我疯狂，我有一种感觉，这对你们中的一些人来说是显而易见的！

PS 我的继承人充分验证减去上述附加的方法...

$(".form_registration_submit").click(function() { 
     $(".qtip").remove(); 
     $("#form_registration").validate({ 
      onfocusout: function(element){ 
       $(".qtip").remove(); 
      }, 
      rules: { 
       name: { 
        required: true, 
        minlength: 3 
       }, 
       firstname: { 
        required: true, 
        minlength: 3 
       }, 
       lastname: { 
        required: true, 
        minlength: 3 
       }, 
       username: { 
        required: true, 
        minlength: 3 
       }, 
       password: { 
        required: true, 
        minlength: 5 
       }, 
       confirm_password: { 
        required: true, 
        minlength: 5, 
        equalTo: "#form_registration_password" 
       }, 
       email: { 
        required: true, 
        email: true, 
        uniqueEmail: true 
       }, 
       topic: { 
        required: "#newsletter:checked", 
        minlength: 2 
       }, 
       agree: "required" 
      }, 
      messages: { 
       name: "Please enter your name", 
       firstname: "Please enter your firstname", 
       lastname: "Please enter your lastname", 
       username: { 
        required: "Please enter a username", 
        minlength: "Your username must consist of at least 2 characters" 
       }, 
       password: { 
        required: "Please provide a password", 
        minlength: "Your password must be at least 5 characters long" 
       }, 
       confirm_password: { 
        required: "Please confirm your password", 
        minlength: "Your password must be at least 5 characters long", 
        equalTo: "Please enter the same password as above" 
       }, 
       email: { 
        required: "Please enter a valid email address", 
        uniqueEmail: jQuery.format("{0} has already been registered") 
       }, 
       agree: "Please accept our policy" 
      }, 
      errorPlacement: function(error, element) { 
       element.qtip(
        { 
         show: { solo: false, ready: true, delay: 0 }, 
         hide: { when:false }, 
         content: eval(error), 
         style: { name: 'dark', border: { width: 1, radius: 1, color:"red" }, tip: 'bottomLeft' }, 
         position: { 
          corner: { target: 'topRight', tooltip: 'bottomLeft' }, 
          adjust: { x: 0 , y: 0 } 
         } 
        }); 
      }, 
      submitHandler: function(form) { 
       $(".qtip").remove(); 
       jQuery(form).ajaxSubmit({ 
        target: "#login_result" 
       }); 
      } 
     }); 
    }); 

Answer 1

您的验证函数实际上并没有返回任何值，因此评估为false。默认情况下，.ajax()请求是异步的，这意味着验证功能在有机会执行成功回调之前结束。

这个问题的.post inside jQuery.validator.addMethod always returns false

Answer 2

也许您的验证码是点击功能（或其他事件）里面，所以它被称为多少次？ 你应该把它放在$（document）.ready（）里面。 此外，你应该发送的数据，因为这：

... 
data: {'email': value}, 
... 

因此它将url编码。如果你不这样做，电子邮件，如'a@a.c&om'将是有效的

Answer 3

重复只需添加异步：false参数为您的Ajax调用，你会好起来