PHP - 迭代虽然Additonial XML节点

Question

我用下面的XML响应结构工作：

<CompressedVehicles> 
<F> 
<RS> 
<R> 
    <VS> 
     <V /> 
     <V /> 
    </VS> 
</R> 
<R> 
    <VS> 
     <V /> 
     <V /> 
    </VS> 
</R> 
</RS> 
</F> 
</CompressedVehicles> 

到目前为止，从一个老乡堆栈溢出成员指导下，我才得以构建基于工作JSON输出下面的PHP代码：

header('Content-Type: application/json'); 

$xml = simplexml_load_file('inventory.xml'); 
$CompressedVehicles = $xml->CompressedVehicles; 

$attributes = array(); 
foreach($CompressedVehicles->F->attributes() as $key => $val) 
{ 
    $attributes[$key] = $val->__toString(); 
} 

$data = array(); 
foreach($CompressedVehicles->F->RS->R->VS->V as $vehicle) 
{ 
    $line = array(); 
    foreach($vehicle->attributes() as $key => $val) 
{ 
    $line[$attributes[$key]] = $val->__toString(); 
} 
$data[] = $line; 
} 

$json = json_encode($data); 
echo $json; 

通过完成之前单个<R>节点这仅迭代。我现在如何追加代码来迭代每个<R>节点？

预先感谢您。

Answer 1

现在，你直接去$CompressedVehicles->F->RS->R->VS->V，只需将其修改为循环各<R>节点：

foreach($CompressedVehicles->F->RS->R as $r) 
{ 

这迭代每个<R>。

然后对于每个<R>，再添巢为$vehicle：

foreach($r->VS->V as $vehicle) 
{ 
// rest of your code