我试图用SBT 0.13.13定义`Task`用`Task`在SBT设置0.13.13
task <<=
(streams in Test,
loadedTestFrameworks in Test,
testLoader in Test,
testGrouping in Test in test,
testExecution in Test in task,
fullClasspath in Test in test,
javaHome in test) flatMap Defaults.allTestGroupsTask
warning: `<<=` operator is deprecated.
Use `key := { x.value }` or `key ~= (old => { newValue })`.
See http://www.scala-sbt.org/0.13/docs/Migrating-from-sbt-012x.html
的<<=
运营商现在已经过时的时候,以消除此设置一个弃用警告,但我不知道如何重写上面的表达式。
我试图把它改写为:
task := Defaults.allTestGroupsTask(
(streams in Test).value,
(loadedTestFrameworks in Test).value,
(testLoader in Test).value,
(testGrouping in Test in test).value,
(testExecution in Test in task).value,
(fullClasspath in Test in test).value,
(javaHome in test).value)
但是用我无法分配Task[A]
到TaskKey
:=
我应该怎么做删除<<=
呢?
'allTestGroupsTask'返回'任务[输出]',让你无论是想在年底或'.taskValue' – laughedelic
申请''.value'在.value'结尾提出错误:非法的动态依赖关系,我找不到'.taskValue',它在哪里? – Eric