转换字符串到

类

我有一个类AuthUser转换字符串到

public class AuthUser 
{ 
    public int UserID { get; set; } 
    public string UserNo { get; set; } 
    public string UserName { get; set; } 
    public string Password { get; set; } 
}

我已转换的类将string。

AuthUser au = new AuthUser(); 
//dtUserDetails is a data table 
if (dtUserDetails.Rows.Count > 0) 
{ 
    DataRow DR = dtUserDetails.Rows[0]; 
    au.UserID = Convert.ToInt32(DR["UserID"].ToString()); 
    au.UserNo = DR["UserNo"].ToString(); 
    au.UserName = DR["UserName"].ToString(); 
    au.Password = DR["Password"].ToString(); 
} 
string userData = au.ToString();

现在我需要将上面的UserData字符串转换回对象类型来检索数据。我怎样才能做到这一点？

来源

2012-08-14 chamara

你检查你的'au.ToString（）获得;'因为你不重写'的ToString（）'为类不会有任何有意义的左得到转换回来！！但你为什么要这样做？ – V4Vendetta 2012-08-14 07:09:16

第一次重写'ToString（）'方法并第二次研究序列化。 – 2012-08-14 07:10:41

我假设你试图持久化数据，然后从持久数据重建对象。查看Serialization。

来源

2012-08-14 07:08:21 Yeonho

哇！！这是他们所说的字符串之间的阅读 – V4Vendetta 2012-08-14 07:10:54

试试这个

可以使这是一个匿名类型

public static string ObjectToXMLString(Object anyObject) 
{ 
    string XmlizedString = string.Empty; 
    XmlSerializer xs = null; 
    XmlTextWriter xmlTextWriter = null; 
    MemoryStream memoryStream = new MemoryStream(); 
    try 
    { 
     xs = new XmlSerializer(anyObject.GetType()); 
     xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.Unicode); 
     xs.Serialize(xmlTextWriter, anyObject); 
     memoryStream = (MemoryStream)xmlTextWriter.BaseStream; 
     XmlizedString = Encoding.Unicode.GetString(memoryStream.ToArray()); 
    } 
    catch 
    { 
     //Do nothing for now 
    } 
    finally 
    { 
     xmlTextWriter.Close(); 
     memoryStream.Close(); 
    } 
    return XmlizedString; 
}

，并再次打开它

/// <summary> 
/// XMLs the string to object. 
/// </summary> 
/// <typeparam name="T">Object of target type</typeparam> 
/// <param name="xml">The XML.</param> 
/// <returns>Instance of target type object filled with corresponding xml data.</returns> 
public static T XMLStringToObject<T>(string xml) 
{ 
    // create default instance of the target type object 
    T targetObject = default(T); 

    // init serializer params 
    XmlSerializer ser = null; 
    StringReader stringReader = null; 
    XmlTextReader xmlReader = null; 
    try 
    { 
     // start deserialization of object 
     ser = new XmlSerializer(typeof(T)); 
     stringReader = new StringReader(xml); 
     xmlReader = new XmlTextReader(stringReader); 
     targetObject = (T)ser.Deserialize(xmlReader); 
    } 
    catch(Exception ex) 
    { 
     // determine what type of object was the target and a copy of the xml being tried and rethrow 
     throw new ArgumentException(String.Format("Exception while deseriliazing to object of type {0}.\n\n=== XML ========\n{1}", typeof(T), xml), ex); 
    } 
    finally 
    { 
     // always close readers to release objectToXMLString 
     xmlReader.Close(); 
     stringReader.Close(); 
    } 

    // return target objectToXMLString 
    return targetObject; 
}

来源

2012-08-14 07:16:50 JohnnBlade

使用序列化，你可以这样创建一个JsonSerilizer：

public static class JsonUtil 
{ 
    public static string Serialize<T>(T value) 
    { 
     using (var ms = new MemoryStream()) 
     { 
      var ser = new DataContractJsonSerializer(typeof(T)); 
      ser.WriteObject(ms, value); 
      byte[] json = ms.ToArray(); 
      ms.Close(); 
      return Encoding.UTF8.GetString(json, 0, json.Length); 
     } 
    } 

    public static T Deserialise<T>(string json) 
    { 
     using (var memoryStream = new MemoryStream(Encoding.Unicode.GetBytes(json))) 
     { 
      var serializer = new DataContractJsonSerializer(typeof(T)); 
      return (T)serializer.ReadObject(memoryStream); 
     } 
    } 

}

使用方法如下：

// Create an object 
var dude = new Dude() { Id = 1, Name = "Joe Smith" }; 

// Turn it into a string 
var json = JsonUtil.Serialize<Dude>(dude); 

// Turn it back into an object 
var cloneDude = JsonUtil.Deserialise<Dude>(json);

来源

2012-08-14 07:42:27

转换字符串到

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