检查冒险游戏中的空房间？

Question

我正在开发一个C++项目的冒险游戏。目标基本上是有一堆房间，由一个班级定义。然后使用地图将它们全部链接在一起。除了检查是否没有空间并确保没有为空房间进行输入之外，我已经做好了一切工作。例如，它会说“这里什么都没有”，然后重新提出用户的移动方向。目前我的程序只是在一个方向没有空间并且方向被选中时崩溃。我目前已经设置好了，至少要确保输入一个有效的方向（北，南，东或西），但它并不检查该方向是否可用。任何人都知道这样做的好方法？

的main.cpp

#include <iostream> 
    #include <string> 
    #include <map> 

    #include "room.h" 

    using namespace std; 

    int main() 
    { 
     /* ---------- Variable Declerations ---------- */ 
     string exitChoice; 

     /* ---------- Room Intialization ---------- */ 
     room *kitchen = new room("Kitchen", "You are in the Kitchen. Pots and pans dangle above your head as you look across the room."); 
     room *diningRoom = new room("Dining Room", "You are in the Dining Room. You see a large table in the center of the room complete with a set of chairs. It seems no one has ate here in quite som time."); 
     room *garage = new room("Garage", "You are in the Garage. There are tools spread across the concerte floor complete with a Jeep Grand Cherokee on jack stands."); 
     room *masterBed = new room("Master Bed Room", "You are in the Bed Room. A large Master Bed greets you as you walk into the room. You can see a large master bath as weel in the backround"); 
     room *hallway = new room("Hallway", "You are in the Hallway. A large set of stairs leads to the second floor, complete with a set to the basement. You also see a grand front door."); 
     room *familyRoom = new room("Family Room", "You are in the Family Room. You see a dark leather couch in front of you as well as a brand new LCD TV. It aappears South Park is on TV."); 
     room *bathRoom = new room("Bath Room", "You are in the Bath Room. A small room containing just a toilet is in front of you."); 
     room *frontLawn = new room("Front Lawn", "You are in the Front Lawn. You are on a pathway and observe freshly cut grass as well as several trees scattered across the yard."); 
     room *backLawn = new room("Back Lawn", "You are in the Back Lawn. You see 'Spot' running around chasing a tennis ball, as well as his dog house. A large wooden fence keeps him in the yard."); 

     /* ----------Room Links---------- */ 

     /* Kitchen */ 
     kitchen->link(diningRoom, "North"); 
     kitchen->link(garage, "East"); 
     kitchen->link(masterBed, "South"); 
     kitchen->link(hallway, "West"); 

     /* Dining Room */ 
     diningRoom->link(kitchen, "South"); 
     diningRoom->link(familyRoom, "West"); 

     /* Master Bed Room */ 
     masterBed->link(kitchen, "North"); 
     masterBed->link(bathRoom, "West"); 

     /* Garage */ 
     garage->link(kitchen, "West"); 
     garage->link(backLawn, "East"); 

     /* Back Lawn */ 
     backLawn->link(garage, "West"); 

     /* Family Room */ 
     familyRoom->link(diningRoom, "East"); 
     familyRoom->link(hallway, "South"); 

     /* Hallway */ 
     hallway->link(familyRoom, "North"); 
     hallway->link(kitchen, "East"); 
     hallway->link(bathRoom, "South"); 
     hallway->link(frontLawn, "West"); 

     /* Front Lawn */ 
     frontLawn->link(hallway, "East"); 

     /* Bath Room */ 
     bathRoom->link(hallway, "North"); 
     bathRoom->link(masterBed, "East"); 

     /* ----------Gameplay---------- */ 
     room *currentRoom = kitchen; 

     while (exitChoice != "quit") 
     { 
      currentRoom->printRoom(); 
      cout << endl; 

      currentRoom->printLiked(); 

      cout << "Which exit? (Or 'quit'):"; 
      cin >> exitChoice; 

      if(exitChoice != "quit" && exitChoice != "North" && exitChoice != "South" && exitChoice != "East" && exitChoice != "West") 
      { 
       cout << "Invalid Entry!" << endl; 
       cout << "Which exit? (Or 'quit'):"; 
       cin >> exitChoice; 
      } 

      cout << "You move to the " << exitChoice << "..." << endl; 
      currentRoom->getLinked(exitChoice); 

      currentRoom = currentRoom->getLinked(exitChoice); 
     } 
    } 

room.h

#ifndef ROOM_H 
#define ROOM_H 

using namespace std; 

#include <string> 
#include <iostream> 
#include <map> 

class room 
{ 
    private: 
     string name; 
     string description; 

    public: 

    /* Constructor Prototypes */ 
    room(string, string); 
    room(string); 

    /* Get Name */ 
    string getName() 
    { 
     return name; 
    } 

    /* Get Description */ 
    string getDescription() 
    { 
     return description; 
    } 

    /* Print Room Information */ 
    void room :: printRoom() 
    { 
     cout << "--" << getName() << "--" << endl; 
     cout << getDescription() << endl; 
    } 

    /* Map */ 
    map<string, room*> exits; 

    /* Link Function*/ 
    void link(room *room, string direction) 
    { 
     exits[direction] = room; 
    } 

    /* Print Linked Rooms */ 
    void printLiked() 
    { 
     map<string, room*> :: iterator it; 

     cout << endl; 

     for(it = exits.begin(); it != exits.end(); ++it) 
     { 
      cout << "Exit: "; 
      cout << it->first << " (" << it->second->getName() << ")" << endl; 

     } 

     cout << endl; 
    } 

    /* Get linked room */ 
    room* getLinked(string direction) 
    { 
     map<string, room*> :: iterator it; 

     it = exits.find(direction); 

     if(it != exits.end()) 
     { 
      return it->second; 
     } 
     else 
     { 
      return NULL; 
     } 


    } 





}; 

#endif 

room.cpp

#include <iostream> 
    #include <string> 
    #include <map> 

    using namespace std; 

    #include "room.h" 

     /* Constructor with Name and Description */ 
     room :: room(string _name, string _description) 
     { 
      name = _name; 
      description = _description; 
     } 


     /* Contrsuctor with Name */ 
     room :: room(string _name) 
     { 
      name = _name; 
     } 

新的main.cpp snipet

 room* possibleNewRoom = currentRoom->getLinked(exitChoice); 

     if (possibleNewRoom != 0) 
     { 
      currentRoom = possibleNewRoom; 

      cout << "You move to the " << exitChoice << "..." << endl; 
      currentRoom->getLinked(exitChoice); 

      currentRoom = currentRoom->getLinked(exitChoice); 
     } 
     else 
     { 
      cout << "There are no exits in that direction." << endl; 
     } 

Answer 1

您需要：

room* possibleNewRoom = currentRoom->getLinked(exitChoice); 

if (possibleNewRoom != 0) 
{ 
    currentRoom = possibleNewRoom; 
} 
else 
{ 
    std::cout << "Ouch - you cannot move that way" << std::endl; 
} 

Answer 2

最常见的方法，这样做是为了向成员介绍到你的房间等级：

class Room { 
    // ... 
    Room *north, *south, *east, *west; 
    // ... 
    Room() : north(NULL), south(NULL), east(NULL), west(NULL) 
    { /* ... */ } 
}; 

然后连接房间彼此像这样：

Room* kitchen = new Room // ... 
Room* hallway = new Room // ... 
kitchen->north = hallway; 
hallway->south = kitchen; 

当您尝试前往一个方向，你只要检查该方向的成员是否NULL：

// Player wants to go north. 
if (this->north == NULL) { 
    // Tell the player that's not possible. 
} else { 
    // OK, we can go to this->north. 
} 

此设置可以让你设置更高级的连接。例如，在向北再向南的情况下，不应将您带到您开始的地方（也许这是一个魔术入口或其中的某些行）。

您可以采取一些关于如何通过设计在TADS (Text Adventure Development System)。