嵌套SQL SELECT

Question

我有一个大的SQL表和我有回报以下查询的一些基本信息：

SELECT 
    CustomerID AS "Customer Name" 
    ,COUNT(ID) AS "Total Emails" 
FROM EmailDatas WHERE Expired = 0 
GROUP BY CustomerID 

结果

Customer Name   Total Emails 
A      1000 
B      9200 
C      11400 

我所试图做的就是计数电子邮件在同一查询返回今天的日期，类似的：

结果

Customer Name   Total Emails   Emails Today 
A      1000     34 
B      9200     7 
C      11400     54 

我可以修改原来的查询返回的信息：

SELECT 
    CustomerID AS "Customer Name" 
    ,COUNT(ID) AS "Total Emails" 
FROM EmailDatas WHERE Expired = 0 and starttime > getdate() 
GROUP BY CustomerID 

我需要的是基本上有这两个查询组合。

希望这是有道理的。

谢谢！

Answer 1

您可以使用条件聚合。像这样的：

SELECT CustomerID AS "Customer Name", 
     COUNT(ID) AS "Total Emails", 
     SUM(CASE WHEN CAST(starttime as date) = CAST(getdate() as date) THEN 1 ELSE 0 END) as "Today's" 
FROM EmailDatas 
WHERE Expired = 0 
GROUP BY CustomerID; 

Answer 2

你也可以这样做。

select t1.CustomerName,t1.TotalEmails, 
case when t2.EmailsToday is null then 0 
else t2.EmailsToday end as EmailsToday 
    from (SELECT 
     CustomerID AS CustomerName 
     ,COUNT(ID) AS TotalEmails 
     FROM EmailDatas WHERE Expired = 0 
     GROUP BY CustomerID) t1 
    left join 
     (SELECT 
     CustomerID AS CustomerName 
     ,COUNT(ID) AS EmailsToday 
     FROM EmailDatas WHERE Expired = 0 and starttime > getdate() 
     GROUP BY CustomerID) t2 
    on t1.CustomerName=t2.CustomerName 

Answer 3

这应该工作

SELECT 
t1.CustomerID AS [Customer Name], 
t1.[Total Emails], 
t2.[Emails Today] 
FROM 
(SELECT 
CustomerID 
,COUNT(ID) AS [Total Emails] 
FROM EmailDatas WHERE Expired = 0 
GROUP BY CustomerID) AS t1 LEFT OUTER JOIN 
(SELECT 
CustomerID 
,COUNT(ID) AS [Emails Today] 
FROM EmailDatas WHERE Expired = 0 and starttime > getdate() 
GROUP BY CustomerID) AS t2 
ON t1.CustomerID = t2.CustomerID