C＃将字典中的值替换为另一个字典

我有2个字典具有相同的键但不同的值。我需要在dictionary1中找到所有等于1的值，并将其替换为dictionary2中的值。我可以编辑第一个字典或更好的想法是将新值保存到另一个字典中，无论哪种方式都很好。我的想法是使用foreach循环，然后在dictionary1 == 1中查找任何值，然后进入dictionary2并为该密钥提取该值并将其保存到字典1或该密钥的另一个字典中。C＃将字典中的值替换为另一个字典

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 

namespace Practice_With_Dictionaries 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 


       object[] keys= new object[5]; 
       keys[0] = "1111"; 
       keys[1] = "2222"; 
       kesy[2] = "3333"; 
       kesy[3] = "4444"; 
       kesy[4] = "5555"; 


       object[] speed = new object[5]; 
       speed[0] = 1; 
       speed[1] = 2; 
       speed[2] = 1; 
       speed[3] = 1; 
       speed[4] = 5; 

       object[] speed2 = new object[5]; 
       speed2[0] = 1; 
       speed2[1] = 2; 
       speed2[2] = 3; 
       speed2[3] = 4; 
       speed2[4] = 5; 





    Dictionary<object, object> dictionary1 = new Dictionary<object,object>(); 
    Dictionary<object, object> dictionar2 = new Dictionary<object, object>(); 

       for (int iRow = 0; iRow < interfaceKeys.Length; iRow++) 
       { 

        dictionary1.Add(keys[iRow], (double)speed[iRow]); 
        dictionary2.Add(keys[iRow], (double)speed2[iRow]); 


       } 


       // for each loop with if statements 




     } 
    } 
}

来源

2017-02-13 Chejua

但是你没有两本字典。你想建立字典吗？ – kat1330

您的代码示例与您的问题不符。你能在你的代码示例中创建字典，以便我们可以看到你开始的数据是什么？您还可以使用集合的初始化语法（https://msdn.microsoft.com/en-us/library/bb531208.aspx） – JamesFaix

我声明了两个字典Dictionary dictionary1 = new Dictionary （）; Dictionary dictionar2 = new Dictionary （）;在上面的代码中。它们具有相同的密钥但不同的值。从我看到使用LINQ的答案是实现我想要的最好方法。 – Chejua

首先，如果你有string为重点，并作为int价值，那么你应该使用Dictionary<string, int>而不是Dictionary<object, object>。

Dictionary<string, int> dictionary1 = new Dictionary<string, int>(); 
Dictionary<string, int> dictionary2 = new Dictionary<string, int>(); 
// fill your dictionaries

现在，如果你总是有两个库之间的匹配键：

var keys = dictionary1.Where(kvp => kvp.Value == 1).Select(kvp => kvp.Key); 
foreach (var key in keys) 
    dictionary1[key] = dictionary2[key];

否则

var keys = dictionary1.Where(kvp => kvp.Value == 1).Select(kvp => kvp.Key); 
foreach (var key in keys) 
{ 
    int value; 
    if (dictionary2.TryGetValue(key, out value)) 
     dictionary1[key] = value; 
}

来源

2017-02-13 23:48:44

您可以使用LINQ和ToDictionary方法（我做了一些改动，以简化代码，我希望这是可以接受的）：

static void Main(string[] args) 
{ 
    var keys = new string[5] { "1111", "2222", "3333", "4444", "5555" }; 

    var speed = new double[5] { 1, 2, 1, 1, 5 }; 

    var speed2 = new double[5] { 1, 2, 3, 4, 5 }; 

    var dictionary1 = new Dictionary<string, double>(); 
    var dictionary2 = new Dictionary<string, double>(); 

    for (int iRow = 0; iRow < keys.Length; iRow++) 
    { 
     dictionary1.Add(keys[iRow], speed[iRow]); 
     dictionary2.Add(keys[iRow], speed2[iRow]); 
    } 

    // the solution 
    var result = dictionary1.ToDictionary(x => x.Key, kv => kv.Value == 1 ? dictionary2[kv.Key] : kv.Value); 
}

来源

2017-02-13 23:54:00 Damian

你可以做这样的事情

var dictionary1 = new Dictionary<string, string> 
{ 
    {"a", "1"}, 
    {"b", "2"}, 
    {"c", "3"}, 
    {"d", "3"} 
}; 



var dictionary2 = new Dictionary<string, string> 
{ 
    {"a", "1"}, 
    {"b", "22"}, 
    {"c", "33"} 
}; 

var result = dictionary1 
    .Where(d => dictionary2.ContainsKey(d.Key) && dictionary2[d.Key] == d.Value);

结果将包含在dictinary1和dictinary2相同的按键与dictinary1值的所有值。

来源

2017-12-06 13:55:48 Nikki

C＃将字典中的值替换为另一个字典

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