对我来说,你的代码是工作的罚款
var latestServerData = [
["name": "Amit", "age": "27", "rollno": 12,"isVisited":true],
["name": "Ananad", "age": "26", "rollno": 10,"isVisited":true],
["name": "Kashyap", "age": "25", "rollno": 11,"isVisited":true],
["name": "Raj", "age": "25", "rollno": 07,"isVisited":true],
["name": "Akshya", "age": "28", "rollno": 13,"isVisited":true]
] as [[String:AnyObject]]
这是为我工作
var dic1 = [String:AnyObject]()
dic1 = latestServerData[4]
dic1["isVisited"] = false as AnyObject
latestServerData[4] = dic1
它也在努力解决
latestServerData[0]["isVisited"] = false as AnyObject
print(latestServerData)
[“name”:Amit,“age”:27,“rollno”:12,“isVisited”:0],[“name”:Ananad,“age”:26,“rollno”:10,“isVisited” :1],[“name”:Kashyap,“age”:25,“rollno”:11,“isVisited”:1],[“name”:Raj,“age”:25,“rollno”:7, isVisited“:1],[”name“:Akshya,”age“:28,”rollno“:13,”isVisited“:0]]
观察数组中的First对象和Last对象。 isVisited“:0
self.latestServerData [4]我觉得应该是latestServerData [4]男子不是? ”自我“ – Govaadiyo
@TofaaniKaanudo没有这并没有改变什么latestServerData声明是全局性不是吗?!特殊功能 –
你可以在控制台上打印latestServerData并放在这里吗? – Govaadiyo