我正在进入python mutliprocessing模块,我遇到了一些问题。我对线程模块非常熟悉,但我需要确保正在执行的进程并行运行。Python多处理 - AssertionError:只能加入子进程
下面是我想要做的事情的概要。请忽略诸如未声明的变量/函数之类的内容,因为我无法完整地粘贴我的代码。
import multiprocessing
import time
def wrap_func_to_run(host, args, output):
output.append(do_something(host, args))
return
def func_to_run(host, args):
return do_something(host, args)
def do_work(server, client, server_args, client_args):
server_output = func_to_run(server, server_args)
client_output = func_to_run(client, client_args)
#handle this output and return a result
return result
def run_server_client(server, client, server_args, client_args, server_output, client_output):
server_process = multiprocessing.Process(target=wrap_func_to_run, args=(server, server_args, server_output))
server_process.start()
client_process = multiprocessing.Process(target=wrap_func_to_run, args=(client, client_args, client_output))
client_process.start()
server_process.join()
client_process.join()
#handle the output and return some result
def run_in_parallel(server, client):
#set up commands for first process
server_output = client_output = []
server_cmd = "cmd"
client_cmd = "cmd"
process_one = multiprocessing.Process(target=run_server_client, args=(server, client, server_cmd, client_cmd, server_output, client_output))
process_one.start()
#set up second process to run - but this one can run here
result = do_work(server, client, "some server args", "some client args")
process_one.join()
#use outputs above and the result to determine result
return final_result
def main():
#grab client
client = client()
#grab server
server = server()
return run_in_parallel(server, client)
if __name__ == "__main__":
main()
这里是我得到的错误:
Error in sys.exitfunc:
Traceback (most recent call last):
File "/usr/lib64/python2.7/atexit.py", line 24, in _run_exitfuncs
func(*targs, **kargs)
File "/usr/lib64/python2.7/multiprocessing/util.py", line 319, in _exit_function
p.join()
File "/usr/lib64/python2.7/multiprocessing/process.py", line 143, in join
assert self._parent_pid == os.getpid(), 'can only join a child process'
AssertionError: can only join a child process
我已经尝试了很多不同的东西来解决这个问题,但我的感觉是,有一些错误,我用这个方式模块。
编辑:
所以我创建了一个将通过模拟客户端/服务器和他们所做的工作重现这个文件 - 我也错过了一个重要的点,这是我在UNIX上运行此。另一个重要的信息是do_work
在我的实际案例涉及使用os.fork()
。如果没有使用os.fork()
,我无法重现错误,因此我假设问题出在那里。在我的真实世界的情况下,这部分代码不是我的,所以我把它当作一个黑盒子(可能是我的错误)。反正这里的代码重现 -
#!/usr/bin/python
import multiprocessing
import time
import os
import signal
import sys
class Host():
def __init__(self):
self.name = "host"
def work(self):
#override - use to simulate work
pass
class Server(Host):
def __init__(self):
self.name = "server"
def work(self):
x = 0
for i in range(10000):
x+=1
print x
time.sleep(1)
class Client(Host):
def __init__(self):
self.name = "client"
def work(self):
x = 0
for i in range(5000):
x+=1
print x
time.sleep(1)
def func_to_run(host, args):
print host.name + " is working"
host.work()
print host.name + ": " + args
return "done"
def do_work(server, client, server_args, client_args):
print "in do_work"
server_output = client_output = ""
child_pid = os.fork()
if child_pid == 0:
server_output = func_to_run(server, server_args)
sys.exit(server_output)
time.sleep(1)
client_output = func_to_run(client, client_args)
# kill and wait for server to finish
os.kill(child_pid, signal.SIGTERM)
(pid, status) = os.waitpid(child_pid, 0)
return (server_output == "done" and client_output =="done")
def run_server_client(server, client, server_args, client_args):
server_process = multiprocessing.Process(target=func_to_run, args=(server, server_args))
print "Starting server process"
server_process.start()
client_process = multiprocessing.Process(target=func_to_run, args=(client, client_args))
print "Starting client process"
client_process.start()
print "joining processes"
server_process.join()
client_process.join()
print "processes joined and done"
def run_in_parallel(server, client):
#set up commands for first process
server_cmd = "server command for run_server_client"
client_cmd = "client command for run_server_client"
process_one = multiprocessing.Process(target=run_server_client, args=(server, client, server_cmd, client_cmd))
print "Starting process one"
process_one.start()
#set up second process to run - but this one can run here
print "About to do work"
result = do_work(server, client, "server args from do work", "client args from do work")
print "Joining process one"
process_one.join()
#use outputs above and the result to determine result
print "Process one has joined"
return result
def main():
#grab client
client = Client()
#grab server
server = Server()
return run_in_parallel(server, client)
if __name__ == "__main__":
main()
如果我删除do_work
使用os.fork()
我没有得到错误和代码的行为就像我本来期望它之前(除产出的传球,我已被接受为我的错误/误解)。我可以将旧代码更改为不使用os.fork(),但我也想知道为什么这会导致此问题,以及是否有可行的解决方案。
编辑2:
我开始省略了接受的答案之前os.fork()的解决方案工作。下面是我有一些调整,可以做的模拟工作量 -
#!/usr/bin/python
import multiprocessing
import time
import os
import signal
import sys
from Queue import Empty
class Host():
def __init__(self):
self.name = "host"
def work(self, w):
#override - use to simulate work
pass
class Server(Host):
def __init__(self):
self.name = "server"
def work(self, w):
x = 0
for i in range(w):
x+=1
print x
time.sleep(1)
class Client(Host):
def __init__(self):
self.name = "client"
def work(self, w):
x = 0
for i in range(w):
x+=1
print x
time.sleep(1)
def func_to_run(host, args, w, q):
print host.name + " is working"
host.work(w)
print host.name + ": " + args
q.put("ZERO")
return "done"
def handle_queue(queue):
done = False
results = []
return_val = 0
while not done:
#try to grab item from Queue
tr = None
try:
tr = queue.get_nowait()
print "found element in queue"
print tr
except Empty:
done = True
if tr is not None:
results.append(tr)
for el in results:
if el != "ZERO":
return_val = 1
return return_val
def do_work(server, client, server_args, client_args):
print "in do_work"
server_output = client_output = ""
child_pid = os.fork()
if child_pid == 0:
server_output = func_to_run(server, server_args)
sys.exit(server_output)
time.sleep(1)
client_output = func_to_run(client, client_args)
# kill and wait for server to finish
os.kill(child_pid, signal.SIGTERM)
(pid, status) = os.waitpid(child_pid, 0)
return (server_output == "done" and client_output =="done")
def run_server_client(server, client, server_args, client_args, w, mq):
local_queue = multiprocessing.Queue()
server_process = multiprocessing.Process(target=func_to_run, args=(server, server_args, w, local_queue))
print "Starting server process"
server_process.start()
client_process = multiprocessing.Process(target=func_to_run, args=(client, client_args, w, local_queue))
print "Starting client process"
client_process.start()
print "joining processes"
server_process.join()
client_process.join()
print "processes joined and done"
if handle_queue(local_queue) == 0:
mq.put("ZERO")
def run_in_parallel(server, client):
#set up commands for first process
master_queue = multiprocessing.Queue()
server_cmd = "server command for run_server_client"
client_cmd = "client command for run_server_client"
process_one = multiprocessing.Process(target=run_server_client, args=(server, client, server_cmd, client_cmd, 400000000, master_queue))
print "Starting process one"
process_one.start()
#set up second process to run - but this one can run here
print "About to do work"
#result = do_work(server, client, "server args from do work", "client args from do work")
run_server_client(server, client, "server args from do work", "client args from do work", 5000, master_queue)
print "Joining process one"
process_one.join()
#use outputs above and the result to determine result
print "Process one has joined"
return_val = handle_queue(master_queue)
print return_val
return return_val
def main():
#grab client
client = Client()
#grab server
server = Server()
val = run_in_parallel(server, client)
if val:
print "failed"
else:
print "passed"
return val
if __name__ == "__main__":
main()
这段代码有一些微调的打印只是为了看看到底发生了什么。我使用了一个multiprocessing.Queue来存储和分享整个流程的输出,并返回到我的主线程中进行处理。我认为这解决了我的问题的python部分,但是我正在处理的代码中仍然存在一些问题。我唯一能说的是,相当于func_to_run
涉及通过ssh发送一个命令,并随输出一起抓取任何err。出于某种原因,这对于执行时间较短的命令来说工作得很好,但对于执行时间/输出大得多的命令来说效果不佳。我试着在我的代码中使用完全不同的工作值来模拟这个,但一直没有能够重现类似的结果。
编辑我使用(再不是我的)3 库代码使用Popen.wait()
的SSH命令,我只是阅读:
Popen.wait()
Wait for child process to terminate. Set and return returncode attribute.Warning This will deadlock when using stdout=PIPE and/or stderr=PIPE and the >child process generates enough output to a pipe such that it blocks waiting for >the OS pipe buffer to accept more data. Use communicate() to avoid that.
我调整了代码,没有缓冲,只是打印,因为它是收到,一切正常。
这里有多个问题。首先:'output.append()'在使用'multiprocessing'模块时可能无法达到你想要的效果。其次,你所报告的问题如下所述:你不能在当前正在执行的'Process'所不具有的'Process'上调用'.join()'。你承认你的例子是合成的,所以很难说出问题的出在哪里。你确定你将'Process()'的结果赋值给一个像本例一样的短暂局部变量?或者你是使用全局变量还是实例变量(例如'self.process_one')? –
对于第一个问题 - 你是对的。它在我使用线程时工作,但可能是因为共享内存空间。进程的变量是本地的。这些进程是否不属于调用进程?我只是在创建它们的函数中加入进程,所以我会假设所有权是可以的,除非有一些调度问题。 –
啊!我现在看到它,你正在'atexit'处理程序中调用'join',但只是因为'multiprocessing'试图自行清理。我会推测这是将一个'Process'实例传递给另一个进程的结果。如果是这样的话,这是IMO在CPython中的一个微妙的错误。 “流程”应该拒绝“pickle”,并在您尝试通过时给予例外。我知道创建最低限度的播放器并不容易,但我认为你会发现它值得你花时间。它会帮助你和我们确定错误的关键因素。 –