2014-11-24 59 views
1

我被时期试图组一串日期,即​​“月”通过DATEADD分组日期和DATEDIFF

首先我声明表:

--inserts 36 dates every 10 days 
create table sales (sales_date datetime, sales_amount decimal(12,2)) 
insert into sales (sales_date,sales_amount) 
select '20140101',1000 union all 
select '20140110',1000 union all 
select '20140120',1000 union all 
select '20140130',1000 union all 
... 

然后我通过查询分组期间条目(尺寸=精度*月)

DECLARE @precision int = 1 --number of months 

SELECT 
dateadd(month, (datediff(month, 0, sales_date)/@precision) * @precision, 0) as FromDate, 
dateadd(month, @precision + (datediff(month, 0, sales_date)/@precision) * @precision, 0) as ToDate, 
count(*) as number 
FROM sales 
GROUP BY 
dateadd(month, (datediff(month, 0, sales_date)/@precision) * @precision, 0), 
dateadd(month, @precision + (datediff(month, 0, sales_date)/@precision) * @precision, 0) 

结果:

Test 1 : precision of 1 month 
From : 01/01/2014, To : 01/02/2014, number : 4 
From : 01/02/2014, To : 01/03/2014, number : 2 
From : 01/03/2014, To : 01/04/2014, number : 3 
From : 01/05/2014, To : 01/06/2014, number : 4 
From : 01/06/2014, To : 01/07/2014, number : 3 
From : 01/07/2014, To : 01/08/2014, number : 3 
From : 01/08/2014, To : 01/09/2014, number : 3 
From : 01/09/2014, To : 01/10/2014, number : 3 
From : 01/10/2014, To : 01/11/2014, number : 3 
From : 01/11/2014, To : 01/12/2014, number : 3 
From : 01/12/2014, To : 01/01/2015, number : 2 

Test 2 : precision of 2 months 
From : 01/01/2014, To : 01/03/2014, number : 6 
From : 01/03/2014, To : 01/05/2014, number : 6 
From : 01/05/2014, To : 01/07/2014, number : 7 
From : 01/07/2014, To : 01/09/2014, number : 6 
From : 01/09/2014, To : 01/11/2014, number : 6 
From : 01/11/2014, To : 01/01/2015, number : 5 

Test 3 : precision of 3 months 
From : 01/01/2014, To : 01/04/2014, number : 9 
From : 01/04/2014, To : 01/07/2014, number : 10 
From : 01/07/2014, To : 01/10/2014, number : 9 
From : 01/10/2014, To : 01/01/2015, number : 8 

Test 4 : precision of 4 months 
From : 01/01/2014, To : 01/05/2014, number : 12 
From : 01/05/2014, To : 01/09/2014, number : 13 
From : 01/09/2014, To : 01/01/2015, number : 11 

一切工作正常,直到测试5:

Test 5 : precision of 5 months 
From : 01/10/2013, To : 01/03/2014, number : 6 
From : 01/03/2014, To : 01/08/2014, number : 16 
From : 01/08/2014, To : 01/01/2015, number : 14 

第一行很讨厌,我需要它在2014年1月1日像以前的精度

有什么办法来克服这个问题开始?

+0

我不明白你是如何得到你得到的输出,也就是说,我期望看到''FROM:''开始选择列列表,但我不这样做,所以这会导致我相信有一个中间步骤你没有在这里展示给我们,这可能是你的“翻译”错误发生的地方。 – 2014-11-24 16:42:07

+0

'和WHERE的sales_date不为空......这一行不需要'AND' – Tanner 2014-11-24 16:43:34

+0

结果只是来自我的C#单元测试,但sql server提供的完全相同;无论如何插入和查询 – codablank1 2014-11-24 16:45:02

回答

0

你并不需要通过精密乘以精度为FROM

这里分裂,再次发生了什么

datediff(month, 0, sales_date)/5 -> 273.6 as it is integer division, it is converting to 273 

进一步273*5 = 1365乘以(SO 3月是失去了应有的到整数除法)

所以这一块应该为你

DECLARE @precision int = 5 --number of months 

SELECT 
dateadd(month, (datediff(month, 0, sales_date)) , 0) as [From], 
dateadd(month, @precision + (datediff(month, 0, sales_date)) , 0) as [To], 
count(*) as number 
FROM sales 
GROUP BY 
dateadd(month, (datediff(month, 0, sales_date)) , 0), 
dateadd(month, @precision + (datediff(month, 0, sales_date)), 0) 
工作
+0

请查看[link](http://dba.stackexchange.com/a/17674/38687)关于'/ @precision)的必要性* @ precision' ;没有它,每个月有一个期间 – codablank1 2014-11-25 16:37:32

+0

@ codablank1,然后使用精度为5.0 – radar 2014-11-25 17:09:52

+0

@ codablank1,我仍然有精度在第二,所以你会得到所有点 – radar 2014-11-25 17:32:38