DATEDIFF在日期

Question

我一直在努力，但我并不擅长tsql。

这就是我得到的，我不能让DateTime计算好。我得到A和B之间的总和，但不是总和。例如在最后一列中，我有一个0让我回到-x。

下面是该过程，以及一些数据是这样的：

Code_Procedure date_evenement     codes_situation   
--------------------------------------------------------------- 
000079500000 2013-05-21 13:07:00.000  COMCFM    
000079500000 2013-05-21 20:24:00.000  PCHCFM  
000079500000 2013-05-22 09:58:00.000  PCHCFM       
000079500000 2013-05-23 00:00:00.000  AARCFM       
000079500000 2013-05-23 00:00:00.000  LIVCFM     
000079600000 2013-05-21 13:07:00.000  COMCFM    
000079600000 2013-05-21 20:24:00.000  PCHCFM    
000079600000 2013-05-22 11:18:00.000  PCHCFM    
000079600000 2013-05-23 00:00:00.000  AARCFM     
000079600000 2013-05-23 00:00:00.000  LIVCFM    

这里是PROC：

DECLARE @COMCFM TABLE(numero_colis VARCHAR(25), date_evenement DATETIME); 
INSERT @COMCFM SELECT TOP(5) numero_colis, date_evenement FROM cartitem_colis_postaux_etats WHERE (code_situation = 'PCH' AND code_justification = 'CFM') 

WHILE (SELECT COUNT(*) FROM @COMCFM) > 0 
BEGIN 
    DECLARE @Colis TABLE(numero_colis VARCHAR(25), date_evenement DATETIME, code_situation_code_justification NVARCHAR(32)); 
    INSERT @Colis SELECT numero_colis, date_evenement, code_situation + code_justification FROM cartitem_colis_postaux_etats WHERE numero_colis = (SELECT TOP(1) numero_colis FROM @COMCFM) ORDER BY numero_colis, date_evenement 

    ;WITH CTE AS 
    (
     Select DISTINCT 
     * 
     ,ROW_NUMBER() OVER(PARTITION BY numero_colis ORDER BY date_evenement ASC) Rn FROM @Colis 
    ),CTE1 AS 
    (
     SELECT DISTINCT 
      A.* 
      ,DATEDIFF(mi, B.date_evenement, A.date_evenement) AS DIFF 
     FROM CTE A INNER JOIN CTE B On B.Rn + 1 = A.Rn 
     UNION All 
     SELECT A.*, 0 FROM CTE A Where Rn = 1 
    ) 

    SELECT 
     A.* 
     ,ISNULL((
      SELECT 
       A.DIFF + B.DIFF 
      FROM CTE1 AS B 
      WHERE A.numero_colis = B.numero_colis 
      AND A.Rn = B.Rn + 1), 0) AS Sums 
    FROM CTE1 AS a 
    ORDER BY numero_colis, Rn ASC 

    DELETE FROM @Colis 
    DELETE FROM @COMCFM WHERE numero_colis = (SELECT TOP(1) numero_colis FROM @COMCFM) 
END 

Answer 1

我真的不知道你想达到的目标。你需要日期差异作为累计值吗？如果你需要这个，有了这个代码

BEGIN 
    DECLARE @Colis TABLE(numero_colis VARCHAR(25), date_evenement DATETIME, code_situation_code_justification NVARCHAR(32)); 
    INSERT @Colis SELECT numero_colis, date_evenement, code_situation + code_justification FROM cartitem_colis_postaux_etats WHERE numero_colis = (SELECT TOP(1) numero_colis FROM @COMCFM) ORDER BY numero_colis, date_evenement 

    ;WITH CTE AS 
    (
     SELECT DISTINCT 
      *, 
      ROW_NUMBER() OVER(PARTITION BY numero_colis ORDER BY date_evenement ASC) Rn 
     FROM @Colis 
    ),CTE1 AS 
    (
     SELECT A.*, 0 AS CummulatedDiff 
     FROM CTE A 
     WHERE Rn = 1 

     UNION ALL 

     SELECT DISTINCT A.*, B.CummulatedDiff + DATEDIFF(mi, B.date_evenement, A.date_evenement) AS CummulatedDiff 
     FROM CTE AS A INNER JOIN 
      CTE1 AS B ON B.Rn + 1 = A.Rn AND B.numero_colis = A.numero_colis 
    ) 

    SELECT * 
    FROM CTE1 AS a 
    ORDER BY numero_colis, Rn ASC 

    DELETE FROM @Colis 
    DELETE FROM @COMCFM WHERE numero_colis = (SELECT TOP(1) numero_colis FROM @COMCFM) 
END 

我希望这进一步把你带到你的目标改变你的存储过程中为BEGIN-END块。