5
我有一个简单的语法如下:ANTLR4:忽略输入空格,但不是那些在字符串
grammar SampleConfig;
line: ID (WS)* '=' (WS)* string;
ID: [a-zA-Z]+;
string: '"' (ESC|.)*? '"' ;
ESC : '\\"' | '\\\\' ; // 2-char sequences \" and \\
WS: [ \t]+ -> skip;
输入的空间完全被忽视,包括字符串文字英寸
final String input = "key = \"value with spaces in between\"";
final SampleConfigLexer l = new SampleConfigLexer(new ANTLRInputStream(input));
final SampleConfigParser p = new SampleConfigParser(new CommonTokenStream(l));
final LineContext context = p.line();
System.out.println(context.getChildCount() + ": " + context.getText());
这将打印输出如下:
3: key="valuewithspacesinbetween"
但是,我预计字符串字面量在白色空间被保留,即
3: key="value with spaces in between"
是否可以纠正语法要实现这种行为,或者我应该重写CommonTokenStream忽略解析过程中的空白?
去除忽略命令正是我需要的 – raghavsood33