TypeError：不能将'int'对象隐式转换为密码系统

Question

即时通讯正在为密码系统创建密码塔赫将字母转换为数字 我做了什么wronge？

abc = "....abcdefg......hijklm........nop.qrst......uvwx.yzæøå" 

def encode(letter): 
    tall = abc.find(letter) 

    return tall 



pw1 = "bb" 
output = "" 

for num in range(28): 
    output = "" 
    for character in pw1: 
     if character in abc: 
      output = output + encode(character) 
     else: 
      output = output + character 


    print(secret) 
    print(output) 

错误代码FOM phyton3.5.2是

Traceback (most recent call last): 
    File "C:/Users/Artde/Desktop/Python/passord system.py", line 17, in <module> 
    output = output + encode(character) 
TypeError: Can't convert 'int' object to str implicitly 

Answer 1

find retruns在串字符的索引所以你的情况函数encode将整数返回，output是字符串，因此 output = output + encode(character)会给出错误所以换成output = output + str(encode(character))