PHP原始数据类型属性

Question

为什么获取任何PHP基元数据类型的属性不会触发错误或警告？

尝试这个PHP的28年3月5日：

$num = 1; 
$str = 'hello'; 
$arr = array(1,2,3); 
$nada = null; 

$num->key1; 
$str->key2; 
$arr->key3; 
$nada->key4; 

任何错误或警告被触发。

Answer 1

您没有启用任何错误报告。当我运行代码，我看到：

PHP Notice: Trying to get property of non-object in /home/5BSpSI/prog.php on line 8 
PHP Notice: Trying to get property of non-object in /home/5BSpSI/prog.php on line 9 
PHP Notice: Trying to get property of non-object in /home/5BSpSI/prog.php on line 10 
PHP Notice: Trying to get property of non-object in /home/5BSpSI/prog.php on line 11 

尝试运行的代码了，但添加error_reporting(E_ALL);作为一线