不显示错误信息

我是这个php的新手。我试图对我的表单进行一些验证，如果它利用我的验证规则，将显示错误消息。我的连接文件。不显示错误信息

<?php 
$con = mysql_connect("localhost","root","") or die('could not connect the server: '. mysql_error()); 
mysql_select_db("interview",$con); 
?>

我validate.php文件

<?php 
require_once('connect.php'); 
$realnameErr = $nickErr = $passwordErr = $emailErr = ""; 
$realname = $nick = $password = $email = ""; 
?>

我的形式

<form name='v2' id='login' method='post' action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"> 

        <fieldset> 
<legend>Login</legend> 
<label for='realname' >Real Name*:</label> 
<input type='text' name='realname' id='realname' maxlength="50" value="<?php echo $realname;?>" /></br> 
<span class="error"><?php echo $realnameErr;?></span> 
<br> 

<label for='nick' >Nick*:</label> 
<input type='text' name='nick' id='nick' maxlength="50" value="<?php echo $nick;?>" /></br> 
<span class="error"><?php echo $nickErr;?></span> 
<br> 
<label for='password' >Password*:</label> 
<input type='password' name='password' id='password' maxlength="50" /></br> 
<span class="error"><?php echo $passwordErr;?></span> 
<br> 
    <label for='email' >Email*:</label> 
<input type='text' name='email' id='email' maxlength="50" value="<?php echo $email;?>"/></br> 
</fieldset> 
<input type='submit' name='submit' value='submit' /> 
</form>

验证从这里开始

<?php 
if ($_SERVER["REQUEST_METHOD"] == "POST") { 
if(isset($_POST['submit'])) { 
if (empty($_POST["realname"])) 
{ 
$realnameErr = "Name is required"; 
} 
else 
{ 
$realname=test_input($_POST["realname"]); 
if(!preg_match("/^[a-zA-z ]*$/",$realname)) 
{ 
$realnameErr = "only letters and white space allowed"; 
}} 
if(empty($_POST["nick"])) 
{ 
$nickErr = "Nick is required"; 
} 
    else { 
$nick=($_POST["nick"]); 
} 
    if(empty($_POST["password"])) 
{ 
$passwordErr = "password is required"; 
} 
else { 
$password=($_POST["password"]); 
} 
if(empty($_POST["email"])) 
{ 
$emailErr = "email is required"; 
} 
else { 
$email=test_input($_POST["email"]); 
if(!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/",$email)) 
{ 
$emailErr = "Invalid email format"; 
}}

检查，然后插入

if((!$realnameErr) && (!$nickErr) && (!$passwordErr) && (!$emailErr)) { 
$query="INSERT INTO `main`"."(realname,nick,password,email)". "VALUES". "('$realname','$nick',SHA('$password'),'$email')"; 
    $res=mysql_query($query); 
echo '<p>Your account has been Successfully created,You are now ready to login. </p>'; 
    } 
}} 

function test_input($data) 
{ 
$data = trim($data); 
$data = stripslashes($data); 
$data = htmlspecialchars($data); 
return $data; 
} 
?>

来源

2013-10-23 black

您需要在显示表单之前获得工作脚本。因为此刻，输出<span class="error"><?php echo $nickErr;?></span>变量$nickErr的时间仍为空，因此不显示任何内容。

来源

2013-10-23 08:07:20

@black我会投它适合你，你仍然可以接受，虽然:-) –

耶，谢谢你们，很高兴我能帮助=） –

试试这个：

// Init 
$errors = array(); 

// Validate Post Data 
if ($_SERVER["REQUEST_METHOD"] == "POST") { 
    if (isset($_POST['submit'])) { 
     if (empty($_POST["realname"])) { 
      $errors[] = "Name is required"; 
     } else { 
      $realname = test_input($_POST["realname"]); 
      if (!preg_match("/^[a-zA-z ]*$/", $realname)) { 
       $errors[] = "only letters and white space allowed"; 
      } 
     } 
     if (empty($_POST["nick"])) { 
      $errors[] = "Nick is required"; 
     } else { 
      $nick = ($_POST["nick"]); 
     } 
     if (empty($_POST["password"])) { 
      $errors[] = "password is required"; 
     } else { 
      $password = ($_POST["password"]); 
     } 
     if (empty($_POST["email"])) { 
      $errors[] = "email is required"; 
     } else { 
      $email = test_input($_POST["email"]); 
      if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/", $email)) { 
       $errors[] = "Invalid email format"; 
      } 
     } 
    } 
} 

// If there is any error 
if (sizeof($errors)) 
{ 
    // display it 
    echo '<div>Following error(s) occured:<br /><br />'. implode('<br />', $errors) .'</div>'; 
} 
else 
{ 
    // proceed with db insert here 
}

来源

2013-10-23 08:33:31 Latheesan

是。它更好地创建一个数组并初始化。感谢名单 – black

不显示错误信息

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