OpenXML库保存excel文件

Question

我有下面的代码，它没有将值保存到单元格和文件中。它显示cell.cellvalue字段的值，但它不写入excel。我不知道如何保存文件。我使用了OpenXml-SDK，我正在为创建的电子表格文档的每个cell/row写入datatable值。

using (SpreadsheetDocument ssd=SpreadsheetDocument.Open(Server.MapPath(@"\ExcelPackageTemplate.xlsx"),true)) 
     { 
      WorkbookPart wbPart = ssd.WorkbookPart; 
      WorksheetPart worksheetPart = wbPart.WorksheetParts.First(); 

      SheetData sheetdata = worksheetPart.Worksheet.GetFirstChild<SheetData>(); 
      string[] headerColumns = new string[] { dt.Columns[0].ColumnName, dt.Columns[1].ColumnName,dt.Columns[2].ColumnName }; 
      DocumentFormat.OpenXml.Spreadsheet.Row r = new DocumentFormat.OpenXml.Spreadsheet.Row(); 
      int RowIndexer = 1; 
      //int colInd=0; 
      r.RowIndex = (UInt32)RowIndexer; 

      string test = ColumnName(RowIndexer); 

      foreach (DataColumn dc in dt.Columns) 
      { 

       DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell(); 
       cell.CellReference = test+RowIndexer; 
       cell.DataType = CellValues.InlineString; 
       cell.InlineString = new InlineString(new Text(dc.ColumnName.ToString())); 
       DocumentFormat.OpenXml.Spreadsheet.CellValue value = new DocumentFormat.OpenXml.Spreadsheet.CellValue(); 

       r.AppendChild(cell); 

       // colInd++; 
      } 

      //r.RowIndex = (UInt32)RowIndexer; 
      RowIndexer = 2; 
      foreach (DataRow dr in dt.Rows) 
      { 
       DocumentFormat.OpenXml.Spreadsheet.Row Row = new DocumentFormat.OpenXml.Spreadsheet.Row(); 
       string Index = ColumnName(RowIndexer); 
       Row.RowIndex = (UInt32)RowIndexer; 
       foreach (object value in dr.ItemArray) 
       { 
        DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell(); 
        cell.DataType = CellValues.InlineString; 
        cell.InlineString = new InlineString(new Text(value.ToString())); 
        cell.CellReference = Index+RowIndexer; 
        // cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(value.ToString()); 
        Row.AppendChild(cell); 

       } 
       RowIndexer++; 

      } 

      worksheetPart.Worksheet.Save(); 
      wbPart.Workbook.Save(); 
      ssd.Close(); 

Answer 1

试试这个：

using (SpreadsheetDocument ssd = SpreadsheetDocument.Open(Server.MapPath(@"\ExcelPackageTemplate.xlsx"), true)) 
{ 
    WorkbookPart wbPart = ssd.WorkbookPart; 
    WorksheetPart worksheetPart = wbPart.WorksheetParts.First(); 

    SheetData sheetdata = worksheetPart.Worksheet.GetFirstChild<SheetData>(); 
    string[] headerColumns = new string[] { dt.Columns[0].ColumnName, dt.Columns[1].ColumnName, dt.Columns[2].ColumnName }; 
    DocumentFormat.OpenXml.Spreadsheet.Row r = new DocumentFormat.OpenXml.Spreadsheet.Row(); 
    DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell(); 
    int RowIndexer = 1; 
    int ColumnIndexer = 1; 

    r.RowIndex = (UInt32)RowIndexer; 
    foreach (DataColumn dc in dt.Columns) 
    { 
     cell = new DocumentFormat.OpenXml.Spreadsheet.Cell(); 
     cell.CellReference = ColumnName(ColumnIndexer) + RowIndexer; 
     cell.DataType = CellValues.InlineString; 
     cell.InlineString = new InlineString(new Text(dc.ColumnName.ToString())); 
     // consider using cell.CellValue. Then you don't need to use InlineString. 
     // Because it seems you're not using any rich text so you're just bloating up 
     // the XML. 

     r.AppendChild(cell); 

     ColumnIndexer++; 
    } 
    // here's the missing part you needed 
    sheetdata.Append(r); 

    RowIndexer = 2; 
    foreach (DataRow dr in dt.Rows) 
    { 
     r = new DocumentFormat.OpenXml.Spreadsheet.Row(); 
     r.RowIndex = (UInt32)RowIndexer; 
     // this follows the same starting column index as your column header. 
     // I'm assuming you start with column 1. Change as you see fit. 
     ColumnIndexer = 1; 
     foreach (object value in dr.ItemArray) 
     { 
      cell = new DocumentFormat.OpenXml.Spreadsheet.Cell(); 
      // I moved it here so it's consistent with the above part 
      // Also, the original code was using the row index to calculate 
      // the column name, which is weird. 
      cell.CellReference = ColumnName(ColumnIndexer) + RowIndexer; 
      cell.DataType = CellValues.InlineString; 
      cell.InlineString = new InlineString(new Text(value.ToString())); 

      r.AppendChild(cell); 
      ColumnIndexer++; 
     } 
     RowIndexer++; 

     // missing part 
     sheetdata.Append(r); 
    } 

    worksheetPart.Worksheet.Save(); 
    wbPart.Workbook.Save(); 
    ssd.Close(); 
} 

一些评论：

• 的的ColumnName（）函数是here。
• 我假设你想要在一行中的列标题和后续行中的数据（因为原始代码有用于计算列名称的行索引）。
• 清理了代码的某些部分，使其更易于阅读，并且列标题和数据行部分在书写风格上更加一致。
• 我建议你考虑使用CellValue而不是InlineString。根据你的代码，你正在导入一个DataTable，而你似乎并不需要丰富的文本，所以InlineString有点矫枉过正，并且可能使得生成的文件变大（臃肿的XML）。使用其中一个，并记住相应地设置DataType。
• 此外，代码仅适用于完全空白的SheetData。

Answer 2

这里有一些可能出现的问题：

• 您创建和添加新的行和单元格：它假定工作表是完全空白的，当你打开它（即：没有行或单元格与相同的索引/地址）。

• 既然你设置CellType到InlineString，你需要设置Cell.InlineString而不是Cell.CellValue

  cell.DataType = CellValues.InlineString; 
  cell.InlineString = new InlineString(New Text(value.TsString())); 
  

• 此外，有什么不对您的有关的 CellReference使用的代码。这些代码部分没有意义：

  cell.CellReference = dc.ColumnName.ToString(); 
  cell.CellReference = value.ToString(); 
  

  单元地址应该是这样的“A1”。您必须查看您的代码才能设置正确的地址。你已经有了rowIndex。您需要获取列名称。这Translate a column index into an Excel Column Name可以帮助。