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我试图根据玩家的数量生成一定数量的按钮。但是,每当我尝试将玩家人数从一个类别移动到另一个类别时,该应用就会崩溃。如何从Java中的第二个类访问变量?
public class MainActivity extends AppCompatActivity {
private EditText[] playersEditText = new EditText[10];
public static Player[] players = new Player[10];
public static int playerCount = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
playersEditText[0] = (EditText) findViewById(R.id.player0);
playersEditText[1] = (EditText) findViewById(R.id.player1);
playersEditText[2] = (EditText) findViewById(R.id.player2);
playersEditText[3] = (EditText) findViewById(R.id.player3);
playersEditText[4] = (EditText) findViewById(R.id.player4);
playersEditText[5] = (EditText) findViewById(R.id.player5);
playersEditText[6] = (EditText) findViewById(R.id.player6);
playersEditText[7] = (EditText) findViewById(R.id.player7);
playersEditText[8] = (EditText) findViewById(R.id.player8);
playersEditText[9] = (EditText) findViewById(R.id.player9);
FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
playerCount = 0;
for (int i = 0; i < 10; i++) {
String name = playersEditText[i].getText().toString();
if (!(name.equals(""))) {
playerCount++;
players[playerCount] = new Player(name);
}
}
if (playerCount < 5)
Toast.makeText(MainActivity.this, "You need at least 5 players " + playerCount, Toast.LENGTH_SHORT).show();
else {
startActivity(new Intent(MainActivity.this, PlayerRevealment.class));
}
}
});
}
}
以上是主要活动。我试图在下面的类中访问对象播放器和int playerCount。
public class PlayerRevealment extends AppCompatActivity {
private int count = MainActivity.playerCount;
private Button[] playerButtons = new Button[count];
//private LinearLayout playerRevealmentLayout;
//private LinearLayout.LayoutParams lp = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_player_revealment);
/*playerRevealmentLayout = (LinearLayout) findViewById(R.id.playerRevealmentLayout);
for (int i = 0; i < playerButtons.length; i++) {
playerButtons[i] = new Button(this);
playerButtons[i].setText("Player " + i); //Change to actual names
playerRevealmentLayout.addView(playerButtons[i], lp);
}*/
Toast.makeText(PlayerRevealment.this, MainActivity.players.length, Toast.LENGTH_SHORT).show();
我试图让他们公共的和静态的,我引用他们MainActivity.playerCount和MainActivity.players [I],但这只是导致应用程序崩溃。有什么建议么?
非常感谢您的帮助。如果您有任何问题,请告诉我。
我想你的解决方案,但它仍然崩溃时,我转向第二项活动。有任何想法吗? –
它因为类Player没有实现android.io.Parcelable而崩溃。 –
,我建议你只传递String数组,因为你只是在MainActivity中收集玩家的名字。我会编辑我的答案。 –